Question

假设我有两个枚举Side和SideDecider，在后一个枚举中，我有一个密钥side，其值应为Side，这样当我使用SideDecider.side，我知道它是Side的值。

enum Side {
  left,
  right,
}

enum SideDecider {
  random,
  other,
  side, // = Side.left | Side.right is what I would like to use
}

// I am looking for a solution resolving something like the following to true
console.log(Side.left === SideDecider.side || Side.right === SideDecider.side)
// error: This condition will always return 'false' since the types 'Side.left' and 'SideDecider.side' have no overlap.

我将如何正确产生这种用法。我是否要错误地使用enums？谢谢您的提前帮助。

Check out example at TypeScript Playground

编辑

我实际上想要实现的目标是相同的，只是使用enums作为字符串，因此我可以将它们用作对象的键，请参见my second example。 Here，有人建议为基于字符串的枚举使用一个类。这是最佳做法吗？

enum Side {
  left = 'left',
  right = 'right',
}

enum SideDecider {
  random = 'random',
  other = 'other',
  side = Side.left | Side.right // Error: Computed values are not permitted in an enum with string valued members
}

const testObj = {
  left: 'something',
  right: 'something',
}

// (1) I am looking for a solution resolving something like the following to [true, true]
console.log([Side.left && SideDecider.side, Side.right && SideDecider.side])

// (2) Is there a way to use SideDecider.side to access keys in testObj?
console.log(testObj[SideDedicer.side])

TypeScript枚举正确使用逻辑或

0 个答案: