Question

我的数据框“ c1”

 steps interval
   <dbl>    <int>
 1     0        0
 2     0        5
 3     0       10
 4     0       15
 5     0       20
 6     0       25
 7     0       30
 8     0       35
 9     0       40
10     0       45
# ... with 278 more rows

PS: Sorry for providing only a small sample from data

我想通过为每50个间隔添加“ interval”列的行来创建新的数据帧'c11'，以便相应地计算每50步（列步）的总和。

我的新数据框应该看起来像

 steps interval
   <dbl>    <int>
 1     0        0
 2     0        50
 3     0       100
 4     10      150
 5     0       200
 6     6       250
 7     20      300
 8     0       350
 9     230     400
10     0       450

我的代码

n=0
j=0
y <- nrow(c1)/50
class(n)
c11 <- data.frame(matrix(NA, nrow = y, ncol = 2)) 

class(c11)
for (i in 1:nrow(c1)) {
  n <- n + c1[i,1]
  if (i%%50==0)
  {
    c11[j,1]<- i
    c11[j,2] <- n
    j <- j+1
    n = 0
  }

}

有人会更正代码，因为它显示了错误的输出？

Answer 1

尝试在package onsource.com.onsourceinspector.data.api; import android.os.Bundle; import android.support.v7.app.AppCompatActivity; import android.view.View; import android.widget.Button; import android.widget.TextView; public class saludos extends AppCompatActivity { private TextView monthsDisplay; int i = 0; private Button next; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_saludos); monthsDisplay = (TextView) findViewById(R.id.espacioFrases); next = (Button) findViewById(R.id.next); next.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { showMonths(); } }); } String[] months = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"}; String monthToDisplay = ""; public void showMonths() { if (i > 11) i = 0; monthsDisplay.setText(months[i++]); } }中使用cut

aggregate

为了更加明确，我们可以将步骤分开

with(c1, aggregate(list(steps = steps), 
     list(interval = cut(interval, c(seq(min(interval), max(interval), 50), Inf), 
     labels = seq(min(interval), max(interval), 50), include.lowest = TRUE)), sum))

使用for循环从旧数据帧形成新数据帧

1 个答案: