Question

这是我的问题。我需要创建一个网络应用程序，该应用程序能够上传两个单独类型的文件（分别是wav文件和midi / MusicXML文件）。现在这行不通。这是我的代码：

app.py

flask import Flask

UPLOAD_FOLDER = '/Users/CatLover/Documents/DataScience/Insight/FrontEnd/Kitty/files/'

app = Flask(__name__)
app.secret_key = "secret key"
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
app.config['MAX_CONTENT_LENGTH'] = 16 * 1024 * 1024

main.py 导入操作系统＃导入魔术导入urllib.request 从应用程序导入应用程序从flask导入Flask，flash，请求，重定向，render_template 从werkzeug.utils导入secure_filename

ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])

def allowed_file(filename):
    return '.' in filename and filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS

@app.route('/')
def upload_form():
    return render_template('upload.html')

@app.route('/', methods=['POST'])
def upload_file():
        if request.method == 'POST':
                print(request.__dict__)
        # check if the post request has the file part
                if 'file' not in request.files:
                        flash('No file part')
                        return redirect(request.url)
                file = request.files['file']
                if file.filename == '':
                        flash('No file selected for uploading')
                        return redirect(request.url)
                if file and allowed_file(file.filename):
                        filename = secure_filename(file.filename)
                        file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
                        flash('File successfully uploaded')
                        return redirect('/')
                else:
                        flash('Allowed file types are txt, pdf, png, jpg, jpeg, gif')
                        return redirect(request.url)

if __name__ == "__main__":
        app.run(host="127.0.0.1",port=int("5003"),debug=True)

templates/upload.html：

<!doctype html>
<title>Python Flask File Upload Example</title>
<h2>Step 1: Select a sheet music file (.xml, .mxl or .mid) to upload</h2>
<p>
    {% with messages = get_flashed_messages() %}
      {% if messages %}
        <ul class=flashes>
        {% for message in messages %}
          <li>{{ message }}</li>
        {% endfor %}
        </ul>
      {% endif %}
    {% endwith %}
</p>
<form method="post" name="sform" action="/" enctype="multipart/form-data">
    <dl>
        <p>
            <input type="file" name="sfile" autocomplete="off" required>
        </p>
    </dl>
    <p>
        <input type="submit" name="ssubmit" value="Submit">
    </p>
</form>
<h2>Step 2: Select a wav file to upload</h2>
<form method="post" name="wform" action="/" enctype="multipart/form-data">
    <dl>
        <p>
            <input type="file" name="wfile" autocomplete="off" required>
        </p>
    </dl>
    <p>
        <input type="submit" name="wsubmit" value="Submit">
    </p>
</form>

Answer 1

请确保在main.py中使用相同的输入字段名称（在upload.html中提到）这是有效的解决方案，该解决方案将仅采用'xml'，'mxl'，'mid'，'wav'扩展名，我们可以根据需要删除多个上传字段，但是根据您的要求，我进行了修改。谢谢

app.py

android.view.InflateException: Binary XML file line #32: Binary XML file line #32: You must supply a layout_height attribute.
 Caused by: java.lang.UnsupportedOperationException: Binary XML file line #32: You must supply a layout_height attribute.

main.py

from flask import Flask

UPLOAD_FOLDER = '/root/Flask'

app = Flask(__name__)
app.secret_key = "secret key"
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
app.config['MAX_CONTENT_LENGTH'] = 16 * 1024 * 1024

templates / upload.html

import os
import magic
from app import app
from flask import Flask, flash, request, redirect, render_template
from werkzeug.utils import secure_filename
ALLOWED_EXTENSIONS = set(['xml', 'mxl','mid','wav'])

def allowed_file(filename):
    return '.' in filename and filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS

@app.route('/')
def upload_form():
    return render_template('upload.html')

@app.route('/', methods=['POST'])
def upload_file():
        if request.method == 'POST':
                print(request.__dict__)
        # check if the post request has the file part
                if 'sfile' not in request.files:
                        flash('No file part')
                        return redirect(request.url)
                file = request.files['sfile']
                if file.filename == '':
                        flash('No file selected for uploading')
                        return redirect(request.url)
                if file and allowed_file(file.filename):
                        filename = secure_filename(file.filename)
                        file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
                        flash('File successfully uploaded')
                        return redirect('/')
                else:
                        flash('Allowed file types are xml,mxl,mid,wav')
                        return redirect(request.url)

if __name__ == "__main__":
        app.run(host="0.0.0.0",port=int("5003"),debug=True)

如何在Flask中分别上传多个文件？

1 个答案: