Question

在我的应用程序中，我有2个过滤器：

1）首先，它引发异常，我打电话给response.sendError(UNAUTHORIZED.getStatusCode(), "My message");

2）第二个用于记录对数据库的请求和响应。

我有一个列“ error_message”，我想将来自过滤器1的错误消息保存在过滤器2中。如何在weblogic上执行此操作？我有javax.servlet.http.HttpServletResponse，我只能取得状态： response.getStatus()

使用Spring我可以打电话 ServletRequestContext.current().getErrorMessage()，但是当我使用weblogic时不起作用。

Answer 1

与其创建自定义HttpServletResponseWrapper，还可以使用ContentCachingResponseWrapper，因为它提供了getContentAsByteArray（）方法。

更多内容-How to read and copy the HTTP servlet response output stream content for logging

public void doFilterInternal(HttpServletRequest servletRequest, HttpServletResponse servletResponse,
        FilterChain filterChain) throws IOException, ServletException {

    HttpServletRequest request = servletRequest;
    HttpServletResponse response = servletResponse;
    ContentCachingRequestWrapper requestWrapper = new ContentCachingRequestWrapper(request);
    ContentCachingResponseWrapper responseWrapper =new ContentCachingResponseWrapper(response);
    try {
        super.doFilterInternal(requestWrapper, responseWrapper, filterChain);

    } finally {

        byte[] responseArray=responseWrapper.getContentAsByteArray();
        String responseStr=new String(responseArray,responseWrapper.getCharacterEncoding());
        System.out.println("string"+responseStr);       
        /*It is important to copy cached reponse body back to response stream
        to see response */
        responseWrapper.copyBodyToResponse();

    }

}

如何从HttpServletResponse获取错误消息

1 个答案: