Question

假设以下代码：

EXAMPLE_1

class Parent_Class {}

class Child_Class extends Parent_Class {
    public $class_name;

    public function __construct() {
      $this->class_name = get_class();
    }
}

$child_instance = new Child_Class();
echo $child_instance->class_name;

/// output will be : 
/// Child_Class

但是这里：

EXAMPLE_2

class Parent_Class {
    public $class_name;

    public function __construct() {
        $this->class_name = get_class();
    }
}

class Child_Class extends Parent_Class {
    public $class_name;

}

$child_instance = new Child_Class();
echo $child_instance->class_name;

/// output will be:
/// Parent_Class

问题： 我如何在EXAMPLE_2中实现EXAMPLE_1的输出，即：如何强制父构造函数方法始终寻找子类名称？

Answer 1

您可以使用get_called_class()代替get_class()：

class Parent_Class
{
    public function __construct()
    {
        $this->class_name = get_called_class();
    }
}

有关更多信息：https://php.net/manual/en/function.get-called-class.php

强制父方法使用子类值

1 个答案: