Question

我有一个数据库，其中记录了用户执行的操作，我想按ID标识从K开头到A开头（从01/01/2019到今天（20 / 06/2019），在此示例中，用户1000将其ID从K更改为A，因为K中的最后一个日期操作早于使用A的第一个操作，每个用户的userID是唯一的，这是我的表，也是用户出于相同的原因，1002的变化也很好。

我的日志表如下

ID      date                  action         USERID
KF12    01/01/2019             Create        1000
KG45    11/06/2019             Create        1002
KI89    06/05/2019             Modify        1003
AO22    20/03/2019             Delete        1000
AI88    20/06/2019             Delete        1002

..

我尝试过的地方还不完整，但是我不知道如何按周计算变更

select distinct USERID, max(DATE_USER) over (partition by USERID) 
FROM
HISTORY 
WHERE 

USERID in (Select distinct USERID
from HISTORY
where ID like 'K%'
and DATE_USER >= to_date('1.1.' || 2019, 'DD.MM.YYYY') 
and DATE_USER < to_date('20.06.' || 2019 , 'DD.MM.YYYY')
INTERSECT
select distinct USERID
from HISTORY
where ID like 'A%'
and DATE_USER >= to_date('1.1.' || 2019, 'DD.MM.YYYY') 
and DATE_USER < to_date('19.06.' || 2019 , 'DD.MM.YYYY'))
and ID like 'A%'
;

在此示例中，预期结果是在（20/03 / 2019,20 / 06/2019）更改的用户（1000，1002），结果必须像这样

WEEKNUMBER    COUNTOFCHANGE
25            1
12            1

Answer 1

使用lag查找上一个ID，按'K'->'A'过滤并根据需要计数

select wk, count(distinct USERID) n
from 
  (select log.*, to_char(dat,'ww') wk, lag(ID) over(partition by USERID order by dat) prev_id
   from log) t
where substr(t.ID,0,1) = 'A' and  substr(t.prev_id,0,1) = 'K'
group by wk

Answer 2

您可以尝试使用自连接来实现以下目的，而不是使用函数：

-- DATA PREPARATION
WITH LOGS(ID, "DATE",ACTION, USERID) AS
(SELECT 'KF12',TO_DATE('01/01/2019','DD/MM/RRRR'),'Create',1000 FROM DUAL UNION ALL
SELECT 'KG45',TO_DATE('11/06/2019','DD/MM/RRRR'),'Create',1002 FROM DUAL UNION ALL
SELECT 'KI89',TO_DATE('06/05/2019','DD/MM/RRRR'),'Modify',1003 FROM DUAL UNION ALL
SELECT 'AO22',TO_DATE('20/03/2019','DD/MM/RRRR'),'Delete',1000 FROM DUAL UNION ALL
SELECT 'AI88',TO_DATE('20/06/2019','DD/MM/RRRR'),'Delete',1002 FROM DUAL)
-- ACTUAL QUERY
SELECT
    WK,
    COUNT(DISTINCT USERID)
FROM
    (
        SELECT
            TO_CHAR(L2."DATE", 'WW') WK,
            L2.USERID
        FROM
            LOGS L1
            JOIN LOGS L2 ON ( L1.USERID = L2.USERID
                              AND L1."DATE" < L2."DATE"
                              AND L1.ID LIKE 'K%'
                              AND L2.ID LIKE 'A%' )
    )
GROUP BY
    WK

输出：

DB Fiddle demo

干杯！

Oracle，SQL请求按周检索数据

2 个答案: