Question

我正在尝试将数据类型Emp的名称，年龄和工资存储到数组中，并要求用户首先全部输入，然后全部输出。

这是使用普通数组的最终所需输出的样子

要输入的用户数：3

第一个输入的重置信息*

第二个输入的重置信息*

第三位输入的重置信息*

-------------------------------------------------- ---- >>

显示信息

姓名年龄工资

QWe 69420

Dvor 42 6900

RT 24 6898

-------------------------------------------------- ------------- >>

关于输入的三名员工的信息。我得到了使用向量的解决方案，但可以通过将其存储在数组中来实现

//Current code

// Included header files
#include <iostream>
#include <string>
#include<algorithm>
#include<vector>

using namespace std;

// Global variable declaration
int sized = 0;

// Struct declaration
struct Employee
{
    string name;
    int age;
    double salary;
};

// Protype
void Showinfo(Employee);

int main()
{
    // Declaring a variable of type Employee
    Employee Emp;

    // Inputting the number of employees that are being inputted
    cout << "Enter the number of the employees that you want to enter into the database: ";
    cin >> sized;

    cout << endl << endl;

    // Reseting the screen
    system("cls");

    // For loop to get the name,age and salary of the given number of employees
    std::vector<Employee> employees;
    for (int i = 0; i < sized; i++)
    {
        cout << "Enter Full name of employee: ";
        cin.ignore();
        getline(cin, Emp.name);
        cout << endl;
        cout << "Enter age of employee: ";
        cin >> Emp.age;
        cout << endl;
        cout << "Enter salary of employee: ";
        cin >> Emp.salary;
        cout << endl;
        employees.push_back(Emp);
        system("cls");
    }

    cout << "Name\t" << "Age\t" << "Wage" << endl;

    for (const auto& e : employees) {
        Showinfo(e);
    }

    cout << "\n" << endl;

    // Pause the console
    cout << "The program has ended" << endl << endl;
    system("pause");
    return 0;
}

// To display/showcase the information received
void Showinfo(Employee Emp)
{
    cout << Emp.name << '\t'
        << Emp.age << '\t'
        << Emp.salary << '\t' << endl;
}

我试图获得相同的输出，但是使用Employee类型的数组来存储雇员信息并在不使用可调整大小的数组/向量的情况下输出它们

就像这段代码I do need some assistance with a creating a loop that displays the information一样，在声明整数大小后，我确实在全局范围内声明了一个Employee类型的数组。如何存储这些值（Employees信息：姓名，年龄和薪金并输出它们，或者不可能那样）

Answer 1

数组的基本操作是索引。索引是通过数组元素在数组中的位置来访问它。在C ++中，具有N个元素的数组具有位置从0到N-1的元素。索引操作用方括号指定，索引值写在内部，例如array[0]或array[N-1]或array[i]，其中i被允许采用0到N-1的值。 / p>

一个粗略的例子：

#include <iostream>

using namespace std;

struct Employee
{
    string name;
    int age;
    double salary;
};

Employee employees[40];

int main()
{
    int size;
    cin >> size;
    if (size > 40) {
        return -1;
    }

    for (int i = 0; i < size; ++i) {
        cin >> employees[i].name >> employees[i].age >> employees[i].salary;
    }

    for (int i = 0; i < size; ++i) {
        cout << employees[i].name << " "
             << employees[i].age << " "
             << employees[i].salary << endl;
    }

    return 0;
}

希望您已经知道for (int i = 0; i < size; ++i)的含义。

Answer 2

这是最终代码

#include <iostream>
#include <iomanip>

using namespace std;

//Global variable declaration
const int arraysize = 40;

struct Employee
{
    string name;
    int age;
    double salary;
};

//Protype
void Showinfo(Employee employees[40], int& size);

//Global array declaration
Employee employees[arraysize];

int main()
{
    int size;
    cout << "Input the size: ";
    cin >> size;

    cout << endl << endl;

    // Reseting the screen
    system("cls");

    if (size > 40) {
        return -1;
    }

    for (int i = 0; i < size; ++i) {
        cout << "Enter a name: ";
        cin >> employees[i].name;
        cout << endl;
        cout << "Enter age: ";
        cin >> employees[i].age;
        cout << endl;
        cout << "Enter the salary: ";
        cin >> employees[i].salary;
        cout << endl;
        system("cls");
    }

    cout << "Displaying Information" << endl;
    cout << "----------------------------------" << endl;

    Showinfo(employees, size);

    cout << "----------------------------------" << endl;
    cout << "\n" << endl;

    cout << "The program has ended" << endl << endl;
    system("pause");
    return 0;
}

void Showinfo(Employee employees[arraysize], int& size) {
    for (int i = 0; i < size; ++i) {
        if (i == 0)
        {
            cout << setw(4) << "Name\t" << "Age\t" << "Wage" << endl << endl;
        }
        cout << setw(4) << employees[i].name << '\t'
            << employees[i].age << '\t'
            << employees[i].salary << endl;
    }
}

如何将预定义数据类型的值存储到数组中并将其输出

2 个答案: