Question

我是Django的新手。我试图使此查询返回按组计数。但这不会对数据进行分组。

  notification = AppointmentNotificationGroupAppointment.objects.filter(receiver__notification_group__group=group).values('receiver__notification_group__group', 'sender__status__name').annotate(pcount=Count('sender__status__name', distinct=True))

它返回：

{'receiver__notification_group__group': '841536_123856', 'sender__status__name': 'Pending', 'pcount': 1},
{'receiver__notification_group__group': '841536_123856', 'sender__status__name': 'Pending', 'pcount': 1},
{'receiver__notification_group__group': '841536_123856', 'sender__status__name': 'Confirmed', 'pcount': 1}, 
{'receiver__notification_group__group': '841536_123856', 'sender__status__name': 'Confirmed', 'pcount': 1}

我在做什么错？我希望它返回不同的记录，并按组进行计数

Answer 1

您也需要致电 order_by(...)

AppointmentNotificationGroupAppointment.objects.filter(receiver__notification_group__group=group).values(
    'receiver__notification_group__group',
    'sender__status__name').annotate(pcount=Count('sender__status__name', distinct=True)
                                     ).order_by('receiver__notification_group__group')

为什么这个工作组不按我希望或期望的方式工作

1 个答案: