目前,我正在使用像这样的PrimeNG对话框:
<button type="button" class="button button-3 button-3a"
(click)="openCloseFront()"><iclass="fa fa-eye"></i>View Image
</button>
<button type="button" class="button button-3 button-3a"
(click)="openCloseBack()"><iclass="fa fa-eye"></i>View Image
</button>
<p-dialog [(visible)]="frontOpened" header="ID Front Side"
[responsive]="true"
[style]="{width: '350px', minWidth: '200px'}"
[minY]="70" [maximizable]="true"
[baseZIndex]="10000">
/* code here with img*/
</p-dialog>
<p-dialog [(visible)]="backOpened" header="ID Back Side"
[responsive]="true"
[style]="{width: '350px', minWidth: '200px'}"
[minY]="70" [maximizable]="true"
[baseZIndex]="10000">
/* code here with img*/
</p-dialog>
然后使用按钮按如下所示打开它们:
public openCloseFront() {
this.frontOpened = !this.frontOpened;
}
public openCloseBack() {
this.backOpened = !this.backOpened;
}
当前行为是,最后打开的对话框是z-index
最大的对话框。这里的问题是,单击该对话框时找不到找到该对话框的方法。我的意思是,当我单击对话框时,我想将z-index
设置为最高,以便将其置于所有人面前。有想法吗?
答案 0 :(得分:1)
上述问题的一种解决方案是:
1)对每个p-dialog
使用标签,并在moveOnTop
上调用(click)
,如下所示:
<p-dialog #pdFront [(visible)]="frontOpened" header="ID Front Side"
[responsive]="true"
[style]="{width: '350px', minWidth: '200px'}"
[minY]="70" [maximizable]="true"
[baseZIndex]="10000" (click)="pdFront.moveOnTop()">
/* code here with img*/
</p-dialog>
<p-dialog #pdBack [(visible)]="backOpened" header="ID Back Side"
[responsive]="true"
[style]="{width: '350px', minWidth: '200px'}"
[minY]="70" [maximizable]="true"
[baseZIndex]="10000" (click)="pdBack.moveOnTop()">
/* code here with img*/
</p-dialog>