从列表中更改第5个号码

Question

我的日历有一个功能

def formatweek(self, theweek, events):
    week = ''
    for d, weekday in theweek:

        #return f'<tr style="color:blue";> {week} </tr>'
        week += self.formatday(d, events)
    return f'<tr> {week} </tr>'

def formatday(self, day, events):
    events_per_day = events.filter(start_time__day=day)
    d = ''
    for event in events_per_day:
        d += f'<li> {event.get_html_url} </li>'

    if day != 0:
        return f"<td><span class='date'>{day}</span><ul> {d} </ul></td>"
    return '<td></td>'

其中theweek是对列表：

 [(1, 0), (2, 1), (3, 2), (4, 3), (5, 4), (6, 5), (7, 6)]
 [(8, 0), (9, 1), (10, 2), (11, 3), (12, 4), (13, 5), (14, 6)]
 [(15, 0), (16, 1), (17, 2), (18, 3), (19, 4), (20, 5), (21, 6)]
 [(22, 0), (23, 1), (24, 2), (25, 3), (26, 4), (27, 5), (28, 6)]
 [(29, 0), (30, 1), (31, 2), (0, 3), (0, 4), (0, 5), (0, 6)]

成对的第一个数字（例如（1））是一个月中的一天（1.januar），第二个是工作日名称的数字（0-星期一，1-星期二等）

d和weekday成为循环中的int。 d =每月的天数（1,2,3,4 ....），Weekday =天数（星期一-0，星期二-1等）。 它为表返回此return f'<tr> {week} </tr>'。我想另外返回f'<tr style="color:blue";> {5 (or 6)} </tr>'的第5和第6个工作日数字（星期六，星期日）。

简单地说：我想度过一个周末变成蓝色。