提取部门每个员工连续工作6个月或更长时间

Question

请在数据下方

Emp.       Date.      Dept
1.         01/21.     Abc
1.         02/15.     Xyz
1.         10/19.     Cba
2.         01/21.     Abc
2.         02/15.     Xyz
2.         04.        Uvw

使用Oracl Sql，如果在部门工作超过6个月的员工让该部门成为当前部门，则我需要在一年中为每个雇员提取

上述数据的预期结果

Emp.          Dept
1.            Xyz.  (Emp workes more than 6 months) 
2.            Uvw.  (No department with 6 months tenure so current department) 

Answer 1

您可以使用以下内容：

我已经根据示例创建了表和数据。

-- Preparing the data
CREATE TABLE EMPLOYEES (
    EMP     NUMBER,
    DATE1   DATE,
    DEPT    VARCHAR2(100)
);

INSERT INTO EMPLOYEES VALUES (
    1,
    TO_DATE('01/21', 'MM/DD'),
    'Abc'
);

INSERT INTO EMPLOYEES VALUES (
    1,
    TO_DATE('02/15', 'MM/DD'),
    'Xyz'
);

INSERT INTO EMPLOYEES VALUES (
    1,
    TO_DATE('10/19', 'MM/DD'),
    'Cba'
);

INSERT INTO EMPLOYEES VALUES (
    2,
    TO_DATE('01/21', 'MM/DD'),
    'Abc'
);

INSERT INTO EMPLOYEES VALUES (
    2,
    TO_DATE('02/15', 'MM/DD'),
    'Xyz'
);

INSERT INTO EMPLOYEES VALUES (
    2,
    TO_DATE('04', 'MM'),
    'Uvw'
);

-

-- Final data in the table
SELECT
    *
FROM
    EMPLOYEES;

-- Your Query
SELECT
    EMP,
    DEPT
FROM
    (
        SELECT
            EMP,
            DEPT,
            ROW_NUMBER() OVER(
                PARTITION BY EMP
                ORDER BY
                    DURATION DESC NULLS LAST
            ) AS RN
        FROM
            (
                SELECT
                    EMP,
                    DATE1,
                    DEPT,
                    MONTHS_BETWEEN(LEAD(DATE1, 1) OVER(
                        PARTITION BY EMP
                        ORDER BY
                            DATE1
                    ), DATE1) AS DURATION
                FROM
                    EMPLOYEES
            )
        WHERE
            DURATION >= 6
            OR DURATION IS NULL
    )
WHERE
    RN = 1;

输出：

希望，这对您有用。

干杯！