Question

我的代码将我添加到列表中的每个新员工追加。我希望它替换我刚刚移除的区域。因此，如果我要删除333并添加666，我希望它成为列表中的第二个而不是最后一个

#include <stdio.h>
#define SIZE 4

struct Employ {
    int ID;
    int age;
    double salary;
};

int main(void) {
    struct Employ emp[SIZE]={{0}};
    int option = 1;
    int nEmp = 0;
    int i;
    int searchedI;
    int check;
    int sID;
    printf("---=== EMPLOYEE DATA ===---\n\n");
    while (option != 0) {
        printf("1. Display Employee Information\n");
        printf("2. Add Employee\n");
        printf("3. Update Employee Salary\n");
        printf("4. Remove Employee\n");
        printf("0. Exit\n\n");
        printf("Please select from the above options: ");
        scanf("%d", &option);
        printf("\n");
        switch (option)
        {
            case 1:
                printf("EMP ID  EMP AGE EMP SALARY\n");
                printf("======  ======= ==========\n");
                for (i = 0; i < nEmp; i++) {
                    printf("%6d%9d%11.2lf\n", emp[i].ID, emp[i].age, emp[i].salary);
                }
                printf("\n");
                break;
            case 2:
                printf("Adding Employee\n");
                printf("===============\n");
                if (nEmp == SIZE) {
                    printf("ERROR!!! Maximum Number of Employees Reached\n\n");
                }
                else {
                    check = 1;
                    while (check) {
                        printf("Enter Employee ID: ");
                        scanf("%d", &emp[nEmp].ID);
                        printf("Enter Employee Age: ");
                        scanf("%d", &emp[nEmp].age);
                        printf("Enter Employee Salary: ");
                        scanf("%lf", &emp[nEmp].salary);
                        if (emp[nEmp].ID < 0 || emp[nEmp].age < 0 || emp[nEmp].salary < 0) printf("\nAll number should be positive\n");
                        else check = 0;
                    }
                    printf("\n");
                    nEmp++;
                }
                break;
            case 3:       //update employee
                printf("Update Employee Salary\n");
                printf("======================\n");
                if (nEmp == 0) {
                    printf("\nNo employee to update\n\n");
                    break;
                }
                do
                {
                    check = 1;
                    printf("Enter Employee ID: ");
                    scanf("%d", &sID);
                    for (i = 0; i < nEmp; i++)
                    {
                        if (emp[i].ID == sID) break;
                        else if (i == nEmp - 1) printf("*** ERROR: Employee ID not found! ***\n");
                    }
                    if (i != nEmp) {
                        printf("The current salary is %.2f\n", emp[i].salary);
                        printf("Enter Employee New Salary: ");
                        scanf("%lf", &emp[i].salary);
                        check = 0;
                        printf("\n");
                    }
                } while (check);
                break;
            case 4:          //remove employee
                printf("Remove Employee\n");
                printf("===============\n");
                if (nEmp == 0) {
                    printf("\nNo employee to remove\n\n");
                    break;
                }
                do
                {
                    check = 1;
                    printf("Enter Employee ID: ");
                    scanf("%d", &sID);
                    for (i = 0; i < nEmp; i++)
                    {
                        if (emp[i].ID == sID) break;
                        else if (i == nEmp - 1) printf("*** ERROR: Employee ID not found! ***\n");
                    }
                    if (i != nEmp) {
                        check = 0;
                        searchedI = i;

                        printf("Employee %d will be removed\n\n", emp[searchedI].ID);

                        for (i = searchedI; i < nEmp; i++)
                        {
                            if (i != nEmp - 1) emp[i] = emp[i + 1];
                            else emp[i].ID = 0;


                        }
                        nEmp -= 1;

                    }

                } while (check);

                break;
            case 0:
                printf("Exiting Employee Data Program. Good Bye!!!\n");
                break;
            default:
                printf("ERROR: Incorrect Option: Try Again\n\n");
                break;
        }

    }
    return 1;
}

原始列表 222 333 444

我希望列表显示 222 666 444

目前显示的结果是 222 444 666

Answer 1

删除值时，可以将其替换为占位符（例如，无穷大），而不是将其从列表中删除。以后要向列表添加新值时，可以在列表中扫描该占位符，然后：

如果存在：将其替换为新值
如果列表不包含此占位符：将值添加到列表的末尾

如何在数组中的特定位置插入

1 个答案: