对ngrx效果的操作类型不匹配

时间:2019-06-18 11:59:15

标签: angular typescript visual-studio-code ngrx ngrx-effects

我用以下3个动作创建了一个动作文件:

export const showLoading = createAction(`[application] Show warning notification`);
export const hideLoading = createAction(`[application] Show error notification`);
export const showHttpResponseError = createAction(`[application] Show success notification`, props<{ error: HttpErrorResponse, nextAction: Action }>());

export type Actions = ReturnType<
typeof showLoading |
typeof hideLoading |
typeof showHttpResponseError
>;

然后我创建了一个这样的效果文件:

@Injectable()
export class ApplicationEffects
{
    constructor(private actions$: Actions, private dialogsService: DialogsService, public notificationsService: NotificationService, private router: Router) { }

    @Effect() public erroHandler$ = this.actions$
        .pipe(
            ofType(ApplicationActions.showHttpResponseError.type),
            switchMap(action => {
                    const emptyAction = { type: 'noop' };
                    const error = HttpErrorHandler.handle(action.error);

                    if (error.redirectTo != null) {
                        this.router.navigate([error.redirectTo]);
                        return of(emptyAction);
                    }

                    if (action.error.status === 400) {
                        this.notificationsService.notifyWarning('AVISO', error.messages);
                    }
                    else {
                        this.dialogsService.errorDialog('ERRO', error.messages[0]);
                    }

                    return action.nextAction ? of(action.nextAction) : of(emptyAction);
                },
            ));
}

但是由于某些原因,VS Code智能感知无法识别switchMap中的动作类型,而是说其类型为never

enter image description here

我想念什么吗?又或者我该如何执行它的类型,因为该动作是使用ngrx动作创建者创建的,因此我没有明确的类型。

2 个答案:

答案 0 :(得分:1)

出于完整性考虑,有多种方法:

1)ofType运算符的类型

ofType<AddAction>(CounterActions.AddAction)

2)输入已注入的动作,就像您已经回答过一样(从NgRx 7开始)

constructor(private actions$: Actions<CounterActions.Actions>

3)与createEffect结合使用createAction(从NgRx 8开始)

foo$ = createEffect(() => this.actions$.pipe(
    ofType(addAction),
    ...
);

答案 1 :(得分:0)

为了将来参考,如果有人遇到相同的问题,解决方案是键入注入的actions$变量:

private actions$: Actions<ApplicationActions.Actions>

然后,智能感知就起作用了,您无需在switchMap中强制输入类型