从特定节点递归获取父节点

Question

我需要创建一个函数，以从树结构中的特定节点返回所有父节点。

这是结构示例：

struct Node
{
    var name: String
    var id: Int
    var parentId: Int?
    var children: [Node]

    init(name: String, id: Int, children: [Node], parentId: Int?)
    {
        self.name = name
        self.id = id
        self.children = children
        self.parentId = parentId
    }
}

这将是一个Node数组。

Array(
    Node("A1", 1, [
        Node ("A11", 11, [
            Node("A111", 111, []),
            Node("A112", 112, [])
            ]
        )]),
    Node("A2", 2, [
        Node ("A21", 21, [
            Node("A211", 211, []),
            Node("A212", 212, [])
            ]
        )]),        
    )
)

如果我选择“ 112”，我应该得到一个这样的数组：

[Node("A1", 1, [...]), Node ("A11", 11, [...]]

有什么想法我该怎么做？

这是一个可测试的示例：

let nodeA111 = Node(name: "A111", id: 111, children: [], parentId: 11)
let nodeA112 = Node(name: "A112", id: 112, children: [], parentId: 11)
let nodeA211 = Node(name: "A211", id: 211, children: [], parentId: 21)
let nodeA212 = Node(name: "A212", id: 212, children: [], parentId: 21)

let nodeA11 = Node(name: "A11", id: 11, children: [nodeA111, nodeA112], parentId: 1)
let nodeA21 = Node(name: "A21", id: 21, children: [nodeA211, nodeA212], parentId: 2)

let nodeA1 = Node(name: "A1", id: 1, children: [nodeA11], parentId: nil)
let nodeA2 = Node(name: "A2", id: 2, children: [nodeA21], parentId: nil)

let nodes: [Node] = [nodeA1, nodeA2]

// This is the function I want to do
func getParentNodes(forNode node: Node) -> [Node]
{
    return []
}

感谢您的帮助。