这是我的代码。我已经经历了,但似乎无法修复错误。我需要做的是从数据库中获取Firebase信息并将其显示在屏幕上。
class homepage:UITableViewController, CLLocationManagerDelegate{
var people = [Userx]()
public override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return people.count
}
public override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath)
as! ViewControllerTableViewCell
let people: Userx
people = people[indexPath.row]
cell.lblName.text = people.Education
cell.lblgenre.text = people.WhatIamConsideringBuying
return cell
}
@IBOutlet weak var table: UITableView!
var locationManager = CLLocationManager()
override func viewDidLoad() {
navigationItem.leftBarButtonItem = UIBarButtonItem(title: "Sign Out", style: .plain, target: self, action: #selector(signOut))
super.viewDidLoad()
let databaseRef = Database.database().reference()
databaseRef.child("Education").observe(DataEventType.value, with: {snapshot in
if snapshot.childrenCount>0{
self.people.removeAll()
for people in snapshot.children.allObjects as! [DataSnapshot] {
let peopleObject = people.value as? [String: AnyObject]
let peopleEducation = peopleObject?["Education"]
let peopleWhatIamConsideringBuying = peopleObject?["WhatIamConsideringBuying"]
let peoplePhotoPosts = peopleObject?["PhotoPosts"]
let people = Userx(Education: peopleEducation as! String?, WhatIamConsideringBuying: peopleWhatIamConsideringBuying as! String?, PhotoPosts: peoplePhotoPosts as AnyObject)
self.people.append(people)
}
self.table.reloadData()
}
})
//这是另一个文件中的Userx:
class Userx {
var Education: String?
var WhatIamConsideringBuying: String?
var PhotoPosts: AnyObject?
init(Education: String?, WhatIamConsideringBuying: String?, PhotoPosts: AnyObject? ){
self.Education = Education
self.WhatIamConsideringBuying = WhatIamConsideringBuying
self.PhotoPosts = PhotoPosts
}
完成后,我希望提取并显示Firebase数据。
答案 0 :(得分:2)
问题在于,您用另一个类型的局部变量people
而不是Userx
中的[Userx]
覆盖了实例属性cellForRowAt
。您应该给本地变量起另一个名字。
public override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath)
as! ViewControllerTableViewCell
let person: Userx = people[indexPath.row]
cell.lblName.text = person.Education
cell.lblgenre.text = person.WhatIamConsideringBuying
return cell
}
与您的问题无关,但您还应遵守Swift命名约定,即变量名称为lowerCamelCase,并在可能的情况下使用不可变的非可选值。使用struct
代替class
还会为您提供一个自动综合的成员初始化器,因此您无需自己创建一个。当您知道变量应具有的类型时(在大多数情况下应该如此),也应该尝试不使用Any
或AnyObject
。
class Userx {
let education: String
let whatIamConsideringBuying: String
let photoPosts: AnyObject
}
答案 1 :(得分:0)
您在init文件中错过了大括号
您的代码
class Userx {
var Education: String?
var WhatIamConsideringBuying: String?
var PhotoPosts: AnyObject?
init(Education: String?, WhatIamConsideringBuying: String?, PhotoPosts: AnyObject? ){
self.Education = Education
self.WhatIamConsideringBuying = WhatIamConsideringBuying
self.PhotoPosts = PhotoPosts
}
固定代码
class Userx {
var Education: String?
var WhatIamConsideringBuying: String?
var PhotoPosts: AnyObject?
init(Education: String?, WhatIamConsideringBuying: String?, PhotoPosts: AnyObject? ){
self.Education = Education
self.WhatIamConsideringBuying = WhatIamConsideringBuying
self.PhotoPosts = PhotoPosts
}
}