我有两个这样的数组:
Array1
$array1 = Array
(
0 => Array
(
'ID' => 101,
'Code' => 1075,
'Date' => '2012-03-03 17:13:12.433'
),
1 => Array
(
'ID' => 103,
'Code' => 175,
'Date' => '2012-09-05 20:30:02.217'
),
2 => Array
(
'ID' => 109,
'Code' => 178,
'Date' => '2012-07-05 20:30:02.217'
)
);
Array2
$array2 = Array
(
0 => Array
(
'Amount' => 1234,
'ID' => 101
),
1 => Array
(
'Amount' => 5656,
'ID' => 101
),
2 => Array
(
'Amount' => 1342,
'ID' => 103
),
3 => Array
(
'Amount' => 0,
'ID' => 0
)
);
我正在使用下面的代码在两个数组上执行连接:
$arr2 = array_column($array2, "ID");
$finalArray = array();
foreach($array1 as $arr){
$key = array_search($arr['ID'], $arr2);
if($key ===false){
$key = array_search(0, $arr2);
}
unset($array2[$key]['ID']);
$finalArray[] = array_merge($arr,$array2[$key]);
}
print_r($finalArray);
使用以上代码的当前输出为:
finalArray
Array
(
[0] => Array
(
[ID] => 101
[Code] => 1075
[Date] => 2012-03-03 17:13:12.433
[Amount] => 1234 //considers only the first entry of ID 101
)
[1] => Array
(
[ID] => 103
[Code] => 175
[Date] => 2012-09-05 20:30:02.217
[Amount] => 1342
)
[2] => Array
(
[ID] => 109
[Code] => 178
[Date] => 2012-07-05 20:30:02.217
[Amount] => 0
)
)
但是,由于在 array2 中,有两个ID为101的条目,但是上面的代码仅对匹配ID为第一个匹配项。 预期的输出是:
所需的输出
Array
(
[0] => Array
(
[ID] => 101
[Code] => 1075
[Date] => 2012-03-03 17:13:12.433
[Amount] => 1234 //amount for first entry of ID 101
)
[1] => Array
(
[ID] => 101
[Code] => 1075
[Date] => 2012-03-03 17:13:12.433
[Amount] => 5656//amount for second entry of ID 101
)
[2] => Array
(
[ID] => 103
[Code] => 175
[Date] => 2012-09-05 20:30:02.217
[Amount] => 1342
)
[3] => Array
(
[ID] => 109
[Code] => 178
[Date] => 2012-07-05 20:30:02.217
[Amount] => 0
)
)
我不知道要使用什么循环。 该代码应为array2的每个匹配ID添加行。 如何修改当前代码,使其提供所需的输出?
答案 0 :(得分:1)
使结果数组成为以ID为键的关联数组。您可以将第一个数组的元素复制到结果中,然后从第二个数组中添加金额。
$finalResult = [];
foreach ($array1 as $arr) {
$finalResult[$arr['ID']] = $arr;
}
foreach ($array2 as $row) {
$id = $row['ID'];
unset($row['ID']);
foreach ($row as $col => $value) {
if (empty($finalResult[$id][$col])) {
$finalResult[$id][$col] = $value;
} else {
$finalResult[$id][$col] += $value;
}
}
}
答案 1 :(得分:1)
$arr2 = array_column($array2, "ID");
$finalArray = array();
foreach($array1 as $arr){
//Get the index of ID which exist in array2. And store in search variable.
$search = array_keys($arr2, $arr['ID']);
if(!$search){
//If ID not exit in array-2, get the index of that ID and store in search variable.
$key = array_search(0, $arr2);
$search[0] = $key;
unset($array2[$key]['ID']);
}
//Fetch search item and merge.
foreach($search as $value){
$finalArray[] = array_merge($arr,$array2[$value]);
}
}
echo "<pre>";
print_r($finalArray);