我有3种型号:
awk '
BEGIN{
key="1,1A,1B,2,3,4,4A,6,Z"
value="1,2,3,4,5,6,7,8,9"
split(key,array1,",")
num=split(value,array2,",")
for(i=1;i<=num;i++){
pair[array1[i]]=array2[i]
}
}
{
for(i=1;i<=NF;i++){
if($i in pair){
$i=pair[$i]
}
}
}
1
' Input_file
我想使用#Appointment
class Appointment(models.Model):
doctor = models.ForeignKey(
Doctor,
on_delete=models.CASCADE,
related_name='doctor_appointment')
patient = models.ForeignKey(
Patient,
on_delete=models.CASCADE,
related_name='patient_appointment')
scheduled = models.DateTimeField(auto_now_add=True)
# Doctor
class Doctor(models.Model):
user_id = models.TextField(unique=True)
first_name = models.CharField(max_length=100, blank=False)
last_name = models.CharField(max_length=100, blank=False)
# Patients
class Patient(models.Model):
user_id = models.TextField(unique=True)
first_name = models.CharField(max_length=100, blank=False)
last_name = models.CharField(max_length=100, blank=False)
执行以下查询:
Django ORM
我想出了这句话:
SELECT
d.first_name,
d.last_name,
d.specialty,
d.address,
a.scheduled
FROM appointment as a
LEFT JOIN patient as p ON p.id=a.patient_id
LEFT JOIN doctor as d ON d.id = a.doctor_id
WHERE p.user_id = '12345';
,但检查其原始查询(ret = Appointment.objects.filter(patient__user_id='12345').values_list('doctor__first_name', 'doctor__last_name', 'scheduled')
)后,我可以看到它已转换为一组ret.query
。
是否可以获取我想要的查询?
答案 0 :(得分:1)
您应该避免考虑SQL查询; ORM的要点是它是基于 object 的。
出于同样的原因,请避免使用values_list
之类的东西,除非您真的知道自己需要一个列表。您应该询问约会对象及其相关的Doctor和Patient对象。
您真正需要做的只是过滤约会并使用select_related
来查询相关模型。然后,Django将根据是否允许空值使用INNER JOIN或LEFT JOIN做正确的事情。
例如,
Appointment.objects.filter(patient__user_id='12345').select_related('patient', 'doctor')