Question

我正在尝试仅获取“ _workAgent”的值，其中_activityStatus“ ==” I“。

请查看我的代码，如下所述，我正在获得价值。

[“ 501”]

0：“ 501”

长度：1

而我只需要在一个变量中获取501值

     "workAgent_ID": [
              {
                "_activityName": "FXL_ACT1",
                "_activityStatus": "I",
                "_userName": "tecnotree",
                "_maxHoldTime": "60",
                "_workAgent": "501"
              },
              {
                "_activityName": "FXL_ACT2",
                "_activityStatus": "N",
                "_userName": null,
                "_maxHoldTime": "120",
                "_workAgent": "510"
              }

   const currentStepPosition = workAgent_ID.filter((item) => {
        return item._activityStatus === "I"
          });
       const workAgentID = currentStepPosition.map(currentStepPosition => {
        return currentStepPosition._workAgent;
           });

Answer 1

map返回数组的新集合。就您而言，我认为您不需要映射currentStepPosition。只需执行以下代码：

const currentStepPosition = workAgent_ID.filter((item) => {
        return item._activityStatus === "I"
          })[0];

const workAgentID  = currentStepPosition._workAgent

Answer 2

这是您可以采用的一种简单方法，如果未找到对象，则此逻辑不会失败。因此，它在两种情况下都适用。

var values =    { "workAgent_ID": [
              {
                "_activityName": "FXL_ACT1",
                "_activityStatus": "I",
                "_userName": "tecnotree",
                "_maxHoldTime": "60",
                "_workAgent": "501"
              },
              {
                "_activityName": "FXL_ACT2",
                "_activityStatus": "N",
                "_userName": null,
                "_maxHoldTime": "120",
                "_workAgent": "510"
              }]}


const index = values.workAgent_ID.findIndex(item => item._activityStatus === "I")
if(index > -1){
  console.log("Result object", values.workAgent_ID[index])
}

如何在React Native中从数组中获取特定值

2 个答案: