Question

我有一个基于httpURLConnection的同步代码，我必须将其转换为异步模式。基本同步模式功能齐全，可以正常工作。为了使其以异步方式实现，我尝试将HttpClient与sendAsync方法（JDK11）结合使用。但是我被困住了。

项目摘要，如下所示： 1）几个测试类，它们扩展了abstractAPITest类。 2）这个abstractAPITest类具有建立连接的功能，现在我正在处理它。 3）class调用测试类的用户 4）主类，它在多个线程中创建User实例并运行它们。

可能应该将打开的连接功能移到User类或Main类中？ idk。

这是我最初的内容（同步）：

byte[] sendRequest(JSONObject jsonObject, String username, String password) throws IOException, URISyntaxException {
        HttpURLConnection httpURLConnection = (HttpURLConnection) (new URL(this.apiUrl)).openConnection();
        if (username != null && password != null) {
            String userPassword = username + ":" + password;
            httpURLConnection.setRequestProperty("Authorization", "Basic " + DatatypeConverter.printBase64Binary(userPassword.getBytes()));
        }
        httpURLConnection.setRequestProperty("Content-Type", "application/json");
        httpURLConnection.setDoOutput(true);
        DataOutputStream dataOutputStream = new DataOutputStream(httpURLConnection.getOutputStream());
        dataOutputStream.write(jsonObject.toString().getBytes());
        dataOutputStream.flush();
        log.info("REST send: JSONObject");
        if (httpURLConnection.getResponseCode() != 200) {
            log.error("REST send error");
            throw new IOException();
        } else {
            byte[] responseBody = null;
            StringBuilder data = new StringBuilder();
            BufferedReader br = new BufferedReader(new InputStreamReader(httpURLConnection.getInputStream()));
            String line;

            while ((line = br.readLine()) != null) {
                data.append(line);
                responseBody = data.toString().getBytes();
            }
            br.close();
            return responseBody;
        }
    }

以及我的异步状态：

byte[] request = jsonObject.toString().getBytes();

        String userPassword;
        if (username != null && password != null) {
            userPassword = username + ":" + password;
        } else {
            throw new NullPointerException("No username and/or password.");
        }

        byte[] responseBody = null;
        byte[] request = jsonObject.toString().getBytes();

        var client = HttpClient.newHttpClient();

        var httpRequest = HttpRequest.newBuilder()
                .uri(new URI(apiUrl))
                .version(HttpClient.Version.HTTP_2)
                .header("Content-Type", "application/json")
                .header("Authorization", "Basic " + DatatypeConverter.printBase64Binary(userPassword.getBytes()))
                .POST(HttpRequest.BodyPublishers.ofByteArray(request))
                .build();

        HttpResponse.BodyHandler<String> bodyHandler = HttpResponse.BodyHandlers.ofString();

        CompletableFuture<HttpResponse<String>> future = client.sendAsync(httpRequest, bodyHandler);
        future.thenApply(HttpResponse::body)
                .thenAccept(System.out::println)
                .join();

        byte[] responseBody = null; // DON'T PAY ATTENTION 
        return responseBody;        // TO THESE TWO LINES
    }

    private static String basicAuthorization(String username, String password) {
        String userPassword = null;
        if (username != null && password != null) {
            userPassword = username + ":" + password;
        }
        return "Basic " + DatatypeConverter.printBase64Binary(userPassword.getBytes());
    }

所以我需要异步方法与同步方法一样，但是异步。那我下一步该怎么办？

将同步httpURLConnection转换为异步HttpClient

0 个答案: