Question

我有一个JSON，它返回一个对象数组，但是我想要做的是返回一个按ID过滤的对象数组。这是我到目前为止构建的代码：

    let objComedien3=[];
      let i=0;

      for (var prop in bc) {
        objComedien3[i] = await app.models.cm_comediens_extraits_mp3.find({ where: { idMedia: bc[prop]} } );
        //here the result is giving me an array of arrays of objects so I had to do this :
        objComedien3[i]= Object.assign({}, objComedien3[i]);
        i++;
      }
      return objComedien3;

我发现的最终结果是：

[
  {
    "0": {
      "idSon": 33274,
      "idMedia": 42084,
      "qfDiffusion": null,
      "qfAccent": null,
      "qfAge": 169,
      "qfCartoon": null,
      "qfDoublage": null,
      "qfInterpretation1": 194,
      "qfInterpretation2": 194,
      "qfInterpretation3": 193,
      "qfImitation": null,
      "qfLangue": 145,
      "qfTimbre": 237,
      "qfType": 245,
      "qfGenre": "Masculin",
      "description": "Techno Music"
    }
  },
  {
    "0": {
      "idSon": 33275,
      "idMedia": 42086,
      "qfDiffusion": null,
      "qfAccent": null,
      "qfAge": 240,
      "qfCartoon": null,
      "qfDoublage": null,
      "qfInterpretation1": 196,
      "qfInterpretation2": 195,
      "qfInterpretation3": 247,
      "qfImitation": null,
      "qfLangue": 147,
      "qfTimbre": 236,
      "qfType": 176,
      "qfGenre": "Masculin",
      "description": "Techno Music"
    }
  }
]

一切都很好，除了我想用idSon替换0并且我不知道如何使用Object.assign或任何其他使用JavaScript的函数来管理它。任何帮助，将不胜感激。非常感谢

Answer 1

尝试一下：

 let objComedien3=[];
      let i=0;

      for (var prop in bc) {
        objComedien3[i] = await app.models.cm_comediens_extraits_mp3.find({ where: { idMedia: bc[prop]} } );
        //here the result is giving me an array of arrays of objects so I had to do this :
        let data= {}
        data[objComedien3[i][0]['idSon']] = objComedien3[i][0]
        objComedien3[i]= Object.assign({}, data);
        i++;
      }
      return objComedien3;

Answer 2

我知道有一个已经被接受的答案，但是要以这种正确的方式进行操作，您应该得到总的结果，然后对其进行处理。

const dataset = await app.models.cm_comediens_extraits_mp3.find(
    { where: { idMedia: {inq: bc} } }//which gets all the media
).then((data)=>{//it is an array already
    return data.reduce((p,c)=>{
        p[c.idSon] = c;//or c.__data if you want the data. Or Object.assign
        return p;
    },{})
})

这样，您不必每次都查询。

Answer 3

您可以通过使用object而不是array来执行此操作，这允许您输入idSon键作为限定符，而不是array中的索引：

let objComedien3 = {};

for (var prop in bc) {
  let result = await app.models.cm_comediens_extraits_mp3.find({ where: { idMedia: bc[prop]} } );
  let clonedResult = Object.assign({}, result[0]);
  objComedien3[clonedResult.idSon] = clonedResult;
}

return objComedien3;

Answer 4

 for (let t of test) {

    //replace your "0" with new "idSon"

    t["idSon"] = t["0"];

    //delete your "0" property object

    delete t["0"];

}

//filter based on Id in this example I Used 33275

let filteredData: any = test.filter((o: any) => o["idSon"].idSon == 33275);

在Javascript中按ID过滤json对象

4 个答案: