如何传递帖子中的数据,以便我们可以调用id?
因为我们试图获取问题的“ qtopic_id”,但该问题不起作用,并且一直在给我一个空值。
我尝试声明qtopic_id = 19来查看其是否保存在qtopic_id列中。 我不必在下面的列中保存特定的id值,这样它就不会仅保存在该特定的id上,而是会保存在其对应的qtopic_id上。
控制器
public function addChoices(){
$this->form_validation->set_rules('ques','Question','required');
$this->form_validation->set_rules('ch_des1','Choices','required');
$this->form_validation->set_rules('ch_des2','Choices','required');
$this->form_validation->set_rules('ch_des3','Choices','required');
$this->form_validation->set_rules('ch_des4','Choices','required');
$this->form_validation->set_rules('ans','Answer','required');
$this->form_validation->set_error_delimiters('<div class="text-danger">','</div>');
if($this->form_validation->run() ){
echo $qtopic_id ;
$data['ques'] = ($this->input->post('ques'));
$data['ch_des1'] = ($this->input->post('ch_des1'));
$data['ch_des2'] = ($this->input->post('ch_des2'));
$data['ch_des3'] = ($this->input->post('ch_des3'));
$data['ch_des4'] = ($this->input->post('ch_des4'));
$data['ans'] = ($this->input->post('ans'));
if($id=$this->queries->registerChoices($data) )
{
$this->session->set_flashdata('message','Test Added Succesfully');
return redirect('admin/testtwo');
}
else {
$this->session->set_flashdata('message','Failed to Add Test');
}
return redirect('admin/testtwo');
}
else {
$this->addQuestion();
}
}
}
型号:
----已更新---
public function registerChoices($data) {
echo $this->input->post('qtopic_id');
$question_arr = [
'ques' => $data['ques'],
'qtopic_id' => 19
];
$choices_arr = [
'ques' => $data['ques'],
'ch_des1' => $data['ch_des1'],
'ch_des2' => $data['ch_des2'],
'ch_des3' => $data['ch_des3'],
'ch_des4' => $data['ch_des4'],
'ans' => $data['ans']
];
// echo "<pre>";
// var_dump($question_arr);
// var_dump($choices_arr);
// exit;
$this->db->insert('tbl_choices',$choices_arr);
$this->db->insert('tbl_question',$question_arr);
return $this->db->insert_id();
}
答案 0 :(得分:0)
您选择寄存器的代码还不清楚。 insert_id
既不接受数据,也不进行插入,它只是在执行插入查询后返回最后插入的ID。我想您想要的是这样的:
function registerChoices($data) {
if ($this->db->insert('tablename', $data)) {
return $this->db->insert_id();
}
return false;
}
用法:
$last_insert_id = $this->somemodel->registerChoices($data);
if ($last_insert_id) {
echo "item with id $last_insert_id was created!";
} else {
show_error('Query failed!');
}