Question

我试图将Bash数组拆分为多列，以便在Markdown文件中显示为表格。

我已经搜索了一种快速的单行代码，以使用Bash，AWK和其他语言来执行此操作。我知道column命令，但是无法将输出保存到变量或文件（stdout）中。我知道您可以循环数组，将值提取到单独的块中，但是必须有一种更快，更有效的方法。

keywords.md

awk
accessibility
bash
behat
c++
cache
d3.js
dates
engineering
elasticsearch
...

columns.sh

local data="$(sort "keywords.md")"     # read contents of file
local data=($data)                     # split contents into an array
local table="||||||\n"                 # create markdown table header
table="${table}|---|---|---|---|---|"
local numColumns=5
# split data into five columns and append to $table variable

我正试图得到这个结果。

||||||
|---|---|---|---|---|
|awk|bash|c++|d3.js|engineering
|accessibility|behat|cache|dates|elasticsearch

result from column command

Answer 1

这是一般方法：

$ cat tst.awk
BEGIN {
    numCols = (numCols ? numCols : 5)
    OFS = "|"
}
{
    colNr = (NR - 1) % numCols + 1
    if ( colNr == 1 ) {
        numRows++
    }
    vals[numRows,colNr] = $0
}
END {
    hdr2 = OFS
    for (colNr=1; colNr<=numCols; colNr++) {
        hdr2 = hdr2 "---" OFS
    }
    hdr1 = hdr2
    gsub(/-/,"",hdr1)
    print hdr1 ORS hdr2

    for (rowNr=1; rowNr<=numRows; rowNr++) {
        printf "|"
        for (colNr=1; colNr<=numCols; colNr++) {
            val = vals[rowNr,colNr]
            printf "%s%s", val, (colNr<numCols ? OFS : ORS)
        }
    }
}

。

$ awk -f tst.awk file
||||||
|---|---|---|---|---|
|awk|accessibility|bash|behat|c++
|cache|d3.js|dates|engineering|elasticsearch

但是它显然不会按照您在问题中要求的顺序输出列，因为我不知道您是如何得出该顺序的。

Answer 2

这是一个perl版本，可以打印出按列减少的值，如您的示例所需输出中一样：

import React, { Fragment, useState } from "react";
import { connect } from "react-redux";
import { addBid } from "../../actions/listing";
import PropTypes from "prop-types";

const BidForm = ({ test, listingId, addBid }) => {
  const [price, setBid] = useState("");

  return (
    <Fragment>
      <h1 className="large text-primary">Bid</h1>

      <form
        className="form-1"
        onSubmit={e => {
          addBid(listingId, { price });
        }}
      >
        <div className="form-group pb">
          <input
            type="text"
            placeholder="Price"
            name="price"
            value={price}
            onChange={e =>
              setBid(e.target.value) & (parseFloat(price) > parseFloat(test))
                ? console.log("greater")
                : console.log("less than")
            }
          />
        </div>

        <input type="submit" className="btn btn-primary my-1" />
      </form>
    </Fragment>
  );
};

BidForm.propTypes = {
  addBid: PropTypes.func.isRequired
};

export default connect(
  null,
  { addBid }
)(BidForm);

用法：

#!/usr/bin/perl
use warnings;
use strict;
use feature qw/say/;

my $ncolumns = 5;

# Read the list of values.
my @data;
while (<>) {
  chomp;
  push @data, $_;
}

# Partition the data up into rows, added down by column
my @columns;
my $nrows = @data / $ncolumns;
#@data = sort { $a cmp $b } @data;
while (@data) {
  my @c = splice @data, 0, $nrows;
  for my $n (0 .. $#c) {
    push @{$columns[$n]}, $c[$n];
  }
}

# And print them out
say '|' x $ncolumns;
say '|', join('|', ('---') x $ncolumns), '|';
for my $r (0 .. $nrows - 1) {
  my @row;
  for my $c (0 .. $ncolumns - 1) {
    my $item = $columns[$r]->[$c];
    push @row, $item if defined $item;
  }
  push @row, ('')x$ncolumns;
  say '|', join('|', @row[0 .. $ncolumns - 1]);
}

如何在Markdown表中将Bash数组拆分为多个列？

2 个答案: