Question

我在页面中使用typeahead，它可以显示数据库中的值，但是该值将是重复的，例如，值是hotel并将hotelhotel保存在数据库中。有人知道解决方案吗？

index.php

<script src="typeahead.min.js"></script>
<script>
$(document).ready(function(){
$('input.typeahead').typeahead({
    name: 'typeahead',
    remote:'search.php?key=%QUERY',
    limit : 20
});
});
</script>

<td><input type="text" name="typeahead" class="typeahead tt-query, cal_amount typeahead" autocomplete="on" spellcheck="false" value="<?php echo $res['supplier'];?>"><input type="hidden" value="" name="typeahead" /></td>

search.php

<?php
$key=$_GET['key'];
$array = array();
include_once("connection.php");

$query=mysqli_query($con, "select * from supplier where cname LIKE '%{$key}%'");
while($row=mysqli_fetch_assoc($query))
{
  $array[] = $row['cname'];

}
echo json_encode($array);
mysqli_close($con);
?>

Answer 1

我使用AJAX通过将Typeahead字段输入作为查询参数来执行PHP脚本，以处理SELECT以获得用于自动完成建议的数据。有关更多详细信息，请单击下面的链接。

https://phppot.com/jquery/bootstrap-autocomplete-with-dynamic-data-load-using-php-ajax/

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.0/jquery.min.js"></script>        
<script src="typeahead.js"></script>
<script>
    $(document).ready(function () {
        $('.typeahead').typeahead({
            source: function (query, result) {
                $.ajax({
                    url: "search.php",
                    data: 'query=' + query,            
                    dataType: "json",
                    type: "POST",
                    success: function (data) {
                        result($.map(data, function (item) {
                            return item;
                        }));
                    }
                });
            }
        });
    });
</script>

<td><input type="text" name="typeahead" class="typeahead tt-query, cal_amount typeahead" autocomplete="on" spellcheck="false" value=""><input type="hidden" value="" name="typeahead" /></td>

search.php

<?php       
    $keyword = strval($_POST['query']);
    $search_param = "{$keyword}%";
    $conn =new mysqli('localhost', 'root', '' , 'test');

    $sql = $conn->prepare("SELECT * FROM supplier WHERE cname LIKE ?");
    $sql->bind_param("s",$search_param);            
    $sql->execute();
    $result = $sql->get_result();
    if ($result->num_rows > 0) {
        while($row = $result->fetch_assoc()) {
        $countryResult[] = $row["cname"];
        }
        echo json_encode($countryResult);
    }
    $conn->close();
?>

解决方案2-不使用ajax。

// Create connection
$conn = new mysqli("localhost", "root", "", "test");
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 
$query=mysqli_query($conn, "select * from supplier");
$data = '';
while($row=mysqli_fetch_assoc($query))
{
    // SELECT to get data for the autocomplete suggestion
    $data.= '"' .$row["cname"]. '",';
}

?>



<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.0/jquery.min.js"></script>        
<script src="typeahead.js"></script>
<script>
$(document).ready(function(){

var substringMatcher = function(strs) {
  return function findMatches(q, cb) {
    var matches, substringRegex;

    // an array that will be populated with substring matches
    matches = [];

    // regex used to determine if a string contains the substring `q`
    substrRegex = new RegExp(q, 'i');

    // iterate through the pool of strings and for any string that
    // contains the substring `q`, add it to the `matches` array
    $.each(strs, function(i, str) {
      if (substrRegex.test(str)) {
        matches.push(str);
      }
    });

    cb(matches);
  };
};

var data = [<?php echo rtrim($data, ',');?>
];

$('.typeahead').typeahead({
  hint: true,
  highlight: true,
  minLength: 1
},
{
  source: substringMatcher(data)
});

});
</script>
<input type="text" name="typeahead" class="typeahead tt-query, cal_amount typeahead" autocomplete="on" spellcheck="false" value=""><input type="hidden" value="" name="typeahead" />

提前输入重复的值

1 个答案: