Question

我有这样的数组结果

main() {
  Function(String) onTextReady;

  if(onTextReady != null) {
    onTextReady('null');
  }

  Function(String) onTextReady2 = (s) => print(s);

  if(onTextReady2 != null) {
    onTextReady2('not null');
  }
}

但是我想这样改变数组：

{"data":{"NamaKecamatan":"BEJI","total":"2","laki":"1","cewe":"1"}}
{"data":{"NamaKecamatan":"BOJONGSARI","total":0,"laki":0,"cewe":0}}
{"data":{"NamaKecamatan":"CILODONG","total":"2","laki":"1","cewe":"1"}}
{"data":{"NamaKecamatan":"CIMANGGIS","total":"4","laki":"2","cewe":"2"}}

这是我在php中的控制器

data: [{NamaKecamatan: "BEJI", total: "46", laki: "18", cewe: "28"},…]
0: {NamaKecamatan: "BEJI", total: "46", laki: "18", cewe: "28"}
1: {NamaKecamatan: "BOJONGSARI", total: "20", laki: "7", cewe: "13"}
2: {NamaKecamatan: "CILODONG", total: "93", laki: "48", cewe: "45"}
3: {NamaKecamatan: "CIMANGGIS", total: "96", laki: "47", cewe: "49"}
4: {NamaKecamatan: "CINERE", total: "13", laki: "7", cewe: "6"}]

请帮助我更改此数据

Answer 1

$data = '[{"data":{"NamaKecamatan":"BEJI","total":"2","laki":"1","cewe":"1"}},
{"data":{"NamaKecamatan":"BOJONGSARI","total":0,"laki":0,"cewe":0}},
{"data":{"NamaKecamatan":"CILODONG","total":"2","laki":"1","cewe":"1"}},
{"data":{"NamaKecamatan":"CIMANGGIS","total":"4","laki":"2","cewe":"2"}}]';

$array_data = json_decode($data, ture);

$result = [];

foreach($array_data as $item) {
    $result['data'][] = $item['data'];
}

return json_encode($result);

Answer 2

您可以按照以下方式进行处理

public function countByKecamatan(){
  $kecamatan = $this->db->query("SELECT IDKecamatan, NamaKecamatan FROM mskecamatan ORDER BY NamaKecamatan ASC")->result_array();
  $i = 0;
  foreach ($kecamatan as $keykecamatan) {
    $result = $this->MsLaporan->dataNullByKecamatan($dateStart, $dateEnd, $kategori, $keykecamatan['IDKecamatan']);
    if ($result == NULL) {
    $row = array(
          "NamaKecamatan" => $keykecamatan['NamaKecamatan'], 
          "total" => 0, 
          "laki" => 0, 
          "cewe" => 0, 
        );
  }else{
    $row = $result[0];
  }
  ($i > 0) ? ($data[] = $row) : ($data = array('data' => $row));
  $i++;
 }
echo json_encode($data);
}

Answer 3

您得到的输出归结为以下2个小问题...

    $data = array(
         "data" => $row,
       );
    echo json_encode($data);

首先，您正在使用要删除的额外级别构建阵列。然后，第二行代码一次回显每个数据。您需要建立所有记录的列表，然后一次性返回全部数据。

public function countByKecamatan(){
  // Create empty array for data
  $data = [];
  $kecamatan = $this->db->query("SELECT IDKecamatan, NamaKecamatan FROM mskecamatan ORDER BY NamaKecamatan ASC")->result_array();
  foreach ($kecamatan as $keykecamatan) {
    $result = $this->MsLaporan->dataNullByKecamatan($dateStart, $dateEnd, $kategori, $keykecamatan['IDKecamatan']);
      if ($result == NULL) {
          $row = array(
              "NamaKecamatan" => $keykecamatan['NamaKecamatan'], 
              "total" => 0, 
              "laki" => 0, 
              "cewe" => 0, 
            );
      }else{
          $row = $result[0];
      }
      // Add new row of data to data to be returned
      $data[] = $row;
   }
   // Return all of the data in JSON format
   return json_encode($data);
}

请注意，这将返回值而不是回显它-如果在调用控制器时，框架需要以其他方式（例如，作为Response对象的一部分）对其进行编码，则可能需要更改此值。

如何更改数组中的结果？

3 个答案: