我基本上是在尝试使用随机方向移动的基本AI。即使我创建了If语句来防止这种情况,也会由于某些原因将其移入其内部。它只会在x坐标上发生,如果我更改顺序,它将在y坐标上发生。在这段代码中,我更改了顺序,它显示了。
我看不到问题,需要快速帮助。 发生的情况的示例(列表显示):
玩家1胜出(蓝色)
[[205,300],[210,300],[215,300],[220,300],[225,300],[225,305],[225,310],[225,315 ],[225、320],[225、325],[225、320]]
dir_x = -5
dir_y = 0
dir_x2 = 5
dir_y2 = 0
x = 600
y = 300
x2 = 200
y2 = 300
cool = True
list1 = []
list2 = []
player1_score = 0
player2_score = 0
speedP1,speedPN1 = 5,-5
speedP2, speedPN2 = 5, -5
while cool == True:
screen.fill(black)
possible_cor = ([5,0],[-5,0],[0,5],[0,-5])
choices = random.choice(possible_cor)
if len(list2) != 0:
if len(list2)%5 == 0:
if dir_y2 == 5:
possible_cor = ([5,0],[-5,0],[0,5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
if dir_y2 == -5:
possible_cor = ([5,0],[-5,0],[0,-5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
if dir_x2 == 5:
possible_cor = ([5,0],[0,5],[0,-5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
if dir_x2 == -5:
possible_cor = ([-5,0],[0,5],[0,-5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
x += dir_x
y += dir_y
x2 += dir_x2
y2 += dir_y2
message_display(str(score1),20,1.9,12,text_objects2)
message_display(str(score2),20,2.1,12,text_objects2)
message_display((":"),20,2,12,text_objects2)
lightbike(blue,x,y)
lightbike(green,x2,y2)
if speedP1 == 5 or speedPN1 == -5:
list1.append([x,y])
if speedP2 == 5 or speedPN2 == -5:
list2.append([x2,y2])
for event in pygame.event.get():
print (event)
#Exit
if event.type == QUIT:
pygame.quit()
sys.exit()
if (event.type == KEYDOWN):
#Player1
if (event.key == 276): #LEFT
if dir_x == 0:
dir_x = speedPN1
if dir_y != 0:
dir_y = 0
if (event.key == 275): #RIGHT
if dir_x == 0:
dir_x = speedP1
if dir_y != 0:
dir_y = 0
if (event.key == 273): #UP
if dir_y == 0:
dir_y = speedPN1
if dir_x != 0:
dir_x = 0
if (event.key == 274): #DOWN
if dir_y == 0:
dir_y = speedP1
if dir_x != 0:
dir_x = 0
#Boundaries
if x + 2 > w or x - 2 < 0 or y + 2 > h or y - 2 < 0:
print ("Player 2 Wins(Green)")
return AI_GAME(total_score,score2+1,score1)
if y2 + 2 > h or y2 - 2 < 0 or x2 + 2 > w or x2 - 2 < 0:
print ("Player 1 Wins(Blue)")
return AI_GAME(total_score,score2,score1+1)
for i,j in zip(list1,list2):
lightbike(blue,i[0],i[1])
lightbike(green,j[0],j[1])
if list1.count(i) > 1:
print ("Player 2 Wins(Green)")
return AI_GAME(total_score,score2+1,score1)
if list2.count(i) > 0:
player2_score += 1
if player1_score != 0:
print ("Player 2 Wins(Green)")
return AI_GAME(total_score,score2+1,score1)
if list1.count(j) > 0:
player1_score += 1
if player2_score != 0:
print ("Player 1 Wins(Blue)")
return AI_GAME(total_score,score2,score1+1)
if list2.count(j) > 1:
print ("Player 1 Wins(Blue)")
print (list2)
pygame.quit()
sys.exit()
if len(list1) > 500:
del list1[0:1]
if len(list2) > 500:
del list2[0:1]
pygame.display.update()
fpsClock.tick(30)
if score1 ==3 or score2 == 3:
cool = False
答案 0 :(得分:0)
我假设您要验证位置(x, y)
的玩家是否与位置(x2, y2)
的玩家冲突。
接下来的(w, h)
(w2, h2)
是播放器的宽度和高度。
使用pygame.Rect
对象和.colliderect()
验证玩家是否会在该位置发生碰撞。
如果他们不冲突,请修改他们的位置:
rect1 = pygame.Rect(x + dir_x, y + dir_y, w, h)
rect2 = pygame.Rect(x2 + dir_x2, y2 + dir_y2, w2, h2)
if not rect1.colliderect(rect2):
x += dir_x
y += dir_y
x2 += dir_x2
y2 += dir_y2
答案 1 :(得分:0)
尽管我不太了解您要做什么,但是我想您遇到的问题是:
if dir_y2 == 5:
possible_cor = ([5,0],[-5,0],[0,5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
if dir_y2 == -5:
possible_cor = ([5,0],[-5,0],[0,-5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
if dir_x2 == 5:
possible_cor = ([5,0],[0,5],[0,-5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
if dir_x2 == -5:
possible_cor = ([-5,0],[0,5],[0,-5])
choices = random.choice(possible_cor)
dir_x2 = choices[0]
dir_y2 = choices[1]
我发现您可能没有考虑到某些问题。每个if块都会更改dir_x2
和dir_y2
的值。因此,下一个if块将使用那些修改后的值来评估其条件。例如,如果dir_x2, dir_y2
在开头是0, 5
,则第一个if块可能会将其更改为5, 0
。但是,第三个if块dir_x2 == 5
的条件现在已满足,因此它也被执行,可能会将dir_x2, dir_y2
进一步更改为0, -5
。我认为这可能不是您想要的。
如果这是问题所在,解决方案是将最后三个if
更改为elif
。现在,每次运行这段代码,最多将执行四个块之一。