Question

我正在制作一个战舰游戏，当放置船只时，它们有时会重叠，函数中的if语句可以防止这种情况，但无济于事

我尝试更改if语句的含义：

import random
# Here I create a grid

a = ["a","_","_","_","_","_","_","_","_","_","_"]
b = ["b","_","_","_","_","_","_","_","_","_","_"]
c = ["c","_","_","_","_","_","_","_","_","_","_"]
d = ["d","_","_","_","_","_","_","_","_","_","_"]
e = ["e","_","_","_","_","_","_","_","_","_","_"]
f = ["f","_","_","_","_","_","_","_","_","_","_"]
g = ["g","_","_","_","_","_","_","_","_","_","_"]
h = ["h","_","_","_","_","_","_","_","_","_","_"]
i = ["i","_","_","_","_","_","_","_","_","_","_"]
j = ["j","_","_","_","_","_","_","_","_","_","_"]
letters = [a,b,c,d,e,f,g,h,i,j]

# This is just asphetic

def board(line_0, Letters):
  print
  print line_0
  for i in Letters:
    print " %s %s %s %s %s %s %s %s %s %s %s" % (i[0],i[1],i[2],i[3],i[4],i[5],i[6],i[7],i[8],i[9],i[10])

#Here's the function
# And what I'm trying to do is to position boat on the grid 

def place_boat(letters, length, BT, Name):
  while len(BT) != length:
    AC_y = random.randint(0,9)
    AC_x = random.randint(0,9)
    if letters[AC_y][AC_x] == "_":  #  These if statements
      rotation = random.randint(0,1)
      if rotation == 0:
        if AC_y >= 5:
          del BT[:]
          for i in range(0, length):
            if letters[AC_y - i][AC_x] == "_":      # Don't work
              BT.append(str(AC_y - i) + str(AC_x))
            else:  
              break            
        if len(BT) != length:
          del BT[:]
          if AC_y <= 6 and AC_y != 0:
            for i in range(0, length):
              if letters[AC_y + i][AC_x] == "_":    # Since they end up
                BT.append(str(AC_y + i) + str(AC_x))
              else:  
                break             
      else:
        if len(BT) != length:
          del BT[:]
          if AC_x >= 5:
            for i in range(0, length):
              if letters[AC_y][AC_x - i] == "_": # reassining multiple values
                BT.append(str(AC_y) + str(AC_x - i))
              else:  
                break             
        if len(BT) != length:
          del BT[:]
          if AC_x <= 6 and AC_y != 0:
            for i in range(0, length):
              if letters[AC_y][AC_x + i] == "_":     # to the same coordinate
                BT.append(str(AC_y) + str(AC_x + i))
              else:  
                break             
  for i in BT:
    letters[int(BT[BT.index(i)][0]) - 1][int(BT[BT.index(i)][1])] = Name
  print BT
  board(line_0, letters)
  return BT
  return letters

#Here are the lists that represent the boat I want to create

AC = []     #   
Bat = []    #   
Cru = []    #   
Sub_1 = []  #   
Sub_2 = []  #   
Des_1 = []  #   
Des_2 = []  #   

#Here I call the function for the individual boats

place_boat(letters, 5, AC, "A")
place_boat(letters, 4, Bat, "B")
place_boat(letters, 3, Cru, "C")
place_boat(letters, 3, Sub_1, "S")
place_boat(letters, 3, Sub_2, "$")
place_boat(letters, 2, Des_1, "D")
place_boat(letters, 2, Des_2, "T")

我希望有一个最终的栅格，该栅格取代随机放置的栅格，并且每个船只都不重叠，例如：

  1 2 3 4 5 6 7 8 9 10
a _ _ _ _ _ _ _ _ T _
b _ _ C _ _ _ _ _ T _
c _ _ C _ _ _ _ _ _ _
d _ _ C _ _ B B B B _
e _ _ _ _ _ _ _ _ _ _
f D D _ _ _ $ $ $ _ _
g _ _ _ _ _ _ _ _ _ _
h _ _ _ _ _ _ _ _ _ _
i _ _ A A A A A _ _ _
j _ _ _ _ _ S S S _ _

但是，如果接收到的船只重叠，例如：

  1 2 3 4 5 6 7 8 9 10
a _ _ _ _ _ _ _ _ _ _
b _ _ T T _ _ A _ _ _
c _ _ C _ _ _ A _ _ _
d _ _ C _ _ B B B B _
e _ _ _ _ _ _ A _ _ _
f _ _ _ _ _ $ $ $ _ _
g _ _ _ D _ _ _ _ _ _
h _ _ _ D S S _ _ _ _
i _ _ _ _ _ _ _ _ _ _
j _ _ _ _ _ _ _ _ _ _

Answer 1

据我所见，您正在检查letters[y][x]是否有重叠，但您正在将船停放在letters[y-1][x]。这可能是问题吗？

如果语句不比较两个值

1 个答案: