Question

仅需重新使用Python并尝试构建一个与文件名匹配的脚本，对其进行重命名，压缩，然后最终从它们构建一个控制文件（我尚未编写）。它适用于放置在目录中的文件，但最后出现错误：FileNotFoundError：[WinError 2]系统找不到指定的文件：'A20190331.txt'->'B20190530.txt'。重命名后是否会在开始时重新运行我的txt_files循环？此时代码可能不是最佳的。

import os
import zipfile

try:
    import zlib
    compression = zipfile.ZIP_DEFLATED
except:
    compression = zipfile.ZIP_STORED




path = 'mypath'

txt_files = []
for root, dirs, files in os.walk(path):
    for file in files:
        txt_files.append(file)


def create_zip(data_dt):
    for files in txt_files:
        if '.py' in files:
            continue
        elif 'A' in files:
            file_name = 'A' + data_dt + '.txt'
            name_full_path = path +'\\'+ file_name
            os.rename(files, file_name)
            zf = zipfile.ZipFile('A' + data_dt+ '.zip', mode='w')
            zf.write(name_full_path, file_name, compress_type=compression)
            zf.close()
        elif 'B' or 'C' in files:
            file_name = 'B' + data_dt + '.txt'
            name_full_path = path +'\\'+ file_name
            os.rename(files, file_name)
            zf = zipfile.ZipFile('B' + data_dt +'.zip', mode='w')
            zf.write(name_full_path, file_name, compress_type=compression)
            zf.close()
        else:
            break

create_zip('20190530')

Answer 1

克里斯托弗。

我立即看到您的问题：

txt_files = []
for root, dirs, files in os.walk(path):
for file in files:
    txt_files.append(file)

我相信您想继续前进：

for root, dirs, files in os.walk(path):
    for file in files:
        txt_files.append(os.path.join(os.path.get_cwd(), file))

让os.path为您处理路径-它可以跨平台移植并且不易出错。

hth

Answer 2

我做了一些修改，请您尝试一下，但是用您的方式，代码将覆盖文件。因此，请尝试使用此脚本，并告诉我要覆盖还是重命名并压缩

def create_zipe(data_dt):
    for files in txt_files:
        if '.py' in files:
            continue
        elif 'ASS' in files:
            file_name = 'A' + data_dt + '.txt'
            name_full_path = path +'/'+ file_name
            os.rename(files, file_name)
            zf = zipfile.ZipFile('A' + data_dt+ '.zip', mode='w')
            zf.write(name_full_path, file_name, compress_type=compression)
            zf.close()
        elif 'C' in files or 'B' in files:
            file_name = 'B' + data_dt + '.txt'
            print(file_name)
            name_full_path = path +'/'+ file_name
            print(name_full_path)
            os.rename(files, file_name)
            zf = zipfile.ZipFile('B' + data_dt+ '.zip', mode='w')
            zf.write(name_full_path, file_name, compress_type=compression)
            zf.close()

重命名和压缩文件Python-FileNotFoundError

2 个答案: