Question

php表单提交转换了JSON格式的URL API来发布该数据，但是数据也不会发布同样通过但无法正常工作的API密钥

   $values->email = $_POST['email'];
   $values->password = $_POST['password'];
   $values->phone = $_POST['phoneno'];
   $values->owner_id = $_POST['operator_id'];
   $values->bank_name = $_POST['bankname'];
   $values->ifsc_code = $_POST['ifsc'];
   $values->last_name = $_POST['lastname'];
   $values->created_by = 'mobiadmin';
   $values->first_name = $_POST['firstname'];
   $values->account_type = $_POST['accounttype'];
   $values->schema = $_POST['schema'];
   $values->merchant_meta = array("id"=> null);
   $values->merchant_name = $_POST['merchantname'];
   $values->account_number = $_POST['accountno'];
   $values->acc_holder_name = $_POST['accountholder'];
   $array = array("records"=>array($values));
   $json_formate = json_encode($array);

   $ch = curl_init('api');                             
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");                                                                     
    curl_setopt($ch, CURLOPT_POSTFIELDS, $json_formate);                                                                  
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);                                                                      
    curl_setopt($ch, CURLOPT_HTTPHEADER, array(                                                                          
        'Content-Type: application/json',
                 'x-api-key:aMqwyQJdA1aqH5GkpG5NR78UyswcHhkEaMZCfrC8',                                                          
        'Content-Length: ' . strlen($json_formate))                                                                       
    );
    $result = curl_exec($ch);

Answer 1

我将为您提供一个非常简单的示例，说明如何设置我的API并从移动应用程序中调用它，或从中获取信息。我已经发表了一些评论，希望对您的项目有进一步的说明或示例。

API

<?php
// this API just fetch articels from a specific URL and view them as a list
// with numbers between from and to
header("Access-Control-Allow-Origin: https://example.com", false); // allowed addresses
header("Access-Control-Allow-Origin: https://www.example.com", false); // allowed addresses
header("Access-Control-Allow-Headers: access");
header("Access-Control-Allow-Methods: GET POST"); // choose GET|POST
header("Access-Control-Allow-Credentials: true");
header('Content-Type: application/json'); // choose type

$file = "classes/Articles.php";

$limit_from = filter_input(INPUT_GET, "limit_from", FILTER_SANITIZE_NUMBER_INT);
$limit_to = filter_input(INPUT_GET, "limit_to", FILTER_SANITIZE_NUMBER_INT);

$articles = new \common\controller\Articles(BASE);
$list = $articles->getArticles((isset($limit_from)) ? $limit_from : 0, (isset($limit_to)) ? $limit_to : 10);
echo json_encode($list);

从PHP页面使用cURL获取api。 可以是单个页面，函数或方法

// create a new cURL resource
// use this option curl_setopt($ch, CURLOPT_URL, "address"); or put address as
// an parameter in curl_init(example address)
$ch = curl_init();

// set URL and other appropriate options
curl_setopt($ch, CURLOPT_URL, "https://example.com/api/public/article/name/example-name");

// Example of sending POST|GET data through cURL
// curl_setopt($ch, CURLOPT_POST, 1);
// curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query(array('postvar1' =>'value1')));

// Here you can add you API key choose Authorization|x-api-key
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Authorization: example-key'
));

curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

// grab URL and pass it to the browser
$data = curl_exec($ch);

// close cURL resource, and free up system resources
curl_close($ch);

return $data;

尽管这是一个GET API，但您可以轻松地将其转换为POST API。

详细了解https://php.net/manual/en/function.http-build-query.php

PHP将JSON数据发布到API

1 个答案: