Question

我有一个看起来像这样的pandas DataFrame：

    Symbol  Date        Time            Bid Price   Bid Exchange    Bid Size    Ask Price   Ask Exchange    Ask Size
0    ABC  2014-03-03  09:30:00.033000   43.16           Z               1       43.69           P               3
1    ABC  2014-03-03  09:30:00.038000   43.17           P               3       43.69           P               3
2    ABC  2014-03-03  09:30:00.039000   43.17           P               4       43.69           P               3
3    ABC  2014-03-03  09:30:00.151000   43.3            P               6       43.69           P               3
4    ABC  2014-03-03  09:30:00.151000   43.3            P               6       43.42           P               4

我想每分钟提取一次数据并进行一些计算。为此，我会反复地向start_time添加1分钟，并将其命名为end_time，然后在start_time和end_time之间选择数据并进行分析；我的代码如下：

import numpy as np
import pandas as pd
import datetime
from datetime import date, time, timedelta

df = pd.read_csv('some_data_file.csv'))

#Converting strings to date and time
df['Date'] = pd.to_datetime(df['Date'])
df['Time'] = pd.to_datetime(df['Time'])
df['Date'] = df['Date'].dt.date
df['Time'] = df['Time'].dt.time

start_date = datetime.date(2014, 3, 3)
end_date = datetime.date(2014, 3, 4)

day_i = df.loc[df['Date']==start_date]

start_time = day_i['Time'][0]

end_time = start_time + timedelta.time(minutes=1)

interval_i = day_i.loc[(day_i['Time'] >= start_time) & (day_i['Time'] <= end_time)]

start_time的格式为datetime.time(9, 30, 0, 33000)。

当我跑步时：

end_time = start_time + timedelta.time(minutes=1)

我收到此错误：

AttributeError: type object 'datetime.timedelta' has no attribute 'time'

Answer 1

首先请确保开始时间和结束时间的类型为时间，而不是日期时间 >。如果需要，转换为时间类型。

type(start_time)

示例：
start_time = (9, 30, 0, 0) end_time = start_time + timedelta(seconds=60)

您应该获得：end_time = (9, 30, 1, 0)

您还可以尝试 pandas between_time（）
myrows = df['Time'].between_time(start_time, end_time)

DataFrame.between_time（开始时间，结束时间，include_start = True，include_end = True）[源代码] 选择一天中特定时间（例如9：00-9：30 AM）之间的值。

如何添加分钟到时间数据？

1 个答案: