以递归方式打印2d数组时,该方法将打印出两列,并以三个额外的间距将第二列重复两次。我该如何解决?
完整代码:
public static void main(String [] args) {
final int ROWS = 2, COLS = 2;
long [][] arr = new long [ROWS][COLS];
setArray(arr, 0, 0);
System.out.println("Numbers in 2d Array: ");
printArray(arr, 0, 0);
}
public static void setArray(long [][] a, int r, int c){
if(r < a.length){
if(c < a[r].length){
a[r][c] = (long)(Math.random() * 100);
setArray(a, r, ++c);
}
setArray(a, ++r, c = 0);
}
}
public static void printArray(long [][]a, int r, int c){
if(r < a.length){
if(c < a[r].length){
System.out.print(a[r][c] + " ");
printArray(a, r, ++c);
}
System.out.println();
printArray(a, ++r, c = 0);
}
}
我遇到问题的方法:
public static void printArray(long [][] a, int r, int c){
if(r < a.lenght){
if(c < a[r].length){
System.out.print(a[r][c] + " ");
printArray(a, r, ++c);
}
System.out.println();
printArray(a, ++r, c = 0);
}
}
预期输出:
二维数组中的数字:
74 16
44 91
实际输出:
二维数组中的数字:
74 16
44 91
44 91
44 91
答案 0 :(得分:1)
问题是当您在打印单个单元格值的第二条printArray()
语句中时,没有退出if
方法。这意味着,当您打印单个单元格值时,也将始终在末尾执行System.out.println();
。这将导致许多新行和数组部分无效的输出。
在System.out.println("Called with r="+r+",c="+c);
方法的开头添加行printArray()
时,将得到以下输出以用于调试:
Numbers in 2d Array:
Called with r=0,c=0
89 Called with r=0,c=1
59 Called with r=0,c=2
Called with r=1,c=0
90 Called with r=1,c=1
71 Called with r=1,c=2
Called with r=2,c=0
Called with r=2,c=0
Called with r=2,c=0
Called with r=1,c=0
90 Called with r=1,c=1
71 Called with r=1,c=2
Called with r=2,c=0
Called with r=2,c=0
Called with r=2,c=0
Called with r=1,c=0
90 Called with r=1,c=1
71 Called with r=1,c=2
Called with r=2,c=0
Called with r=2,c=0
Called with r=2,c=0
从调试行可以看到,行索引和列索引并不是一直都在上升,而是从行索引2
返回到索引1
。这应该表明您的printArray();
方法有什么问题。
要解决此问题,只需在第二个return;
中使用if()
语句即可尽早退出该方法(而不调用System.out.println();
行)或使用if-else
语句以打印单元格值 OR 或生成新行。
public static void printArray(long [][]a, int r, int c){
if(r < a.length){
if(c < a[r].length){
System.out.print(a[r][c] + " ");
printArray(a, r, ++c);
return; // <----------- here
} // <--- or use an "else" block here
System.out.println();
printArray(a, ++r, c = 0);
}
}
答案 1 :(得分:0)
看起来像一个作业问题。因此,我建议逐步执行以查找问题。如果您仍然陷于困境,我的提示是考虑何时返回。