Question

我的代码：

from datetime import datetime, date,time
timeobj = time(0, 5)
start = datetime.now().time()
time1 = datetime.combine(date.min, start) - datetime.combine(date.min, timeobj)
tx = start+time1 # throws error in here
if (start >= tx):
   pass #do stuff

我遇到此错误：

TypeError：+不支持的操作数类型：“ datetime.time”和“ datetime.timedelta”

有人可以帮助我解决此问题吗？我只想使用上面的"if"语句。

Answer 1

这是我的建议：

from datetime import datetime, date, time
timeobj = time(0,5)
start = datetime.combine(date.min, datetime.now().time())
time1 = datetime.combine(date.min, start) - datetime.combine(date.min, timeobj)
tx = (start+time1).time()
if start.time() > tx:
    pass # do stuff

Answer 2

这里的问题是start是datetime.time对象，time1是两个datetime.datetimes之间的时间增量，因此+运算符对于将它们组合起来没有意义。错误。我不确定您要达到的目标，但总体来说，请确保您的start变量属于可以添加timedelta的类型，例如：

from datetime import datetime, date,time
timeobj = time(0, 5)
start_time =  datetime.now().time()
start = datetime.combine(date(1, 2, 3), start_time)  # here start is a datetime object
time1 = datetime.combine(date.min, start_time) - datetime.combine(date.min, timeobj)
tx = start+time1

Answer 3

不要太复杂，您只需要比较start和timeobj（5AM）。为什么？这是因为您只是在比较当前时间是否小于5AM。让我们做一些基本的代数。

given:
time1 = start - timeobj
tx = start + time1

thus: if (start >= tx) is the same with
      start >= start + start - timeobj
      0 >= start - timeobj
      timeobj >= start 
  (is current time earlier than 5am?)

更新脚本：

from datetime import datetime, date,time
timeobj = time(0, 5)
start = datetime.now().time()
#time1 = datetime.combine(date.min, start) - datetime.combine(date.min, timeobj)
#tx = start+time1 # throws error in here
if (timeobj >= start ):
    print('pass')
    pass #do stuff

在python中添加特定时间

3 个答案: