好,所以这应该不算困难,但是我在画一个空白。因此,该程序的想法是找到仅在文本中出现一次的单词,然后将其大写。这是完整的代码:
from collections import Counter
from string import punctuation
path = input("Path to file: ")
with open(path) as f:
word_counts = Counter(word.strip(punctuation) for line in f for word in line.replace(")", " ").replace("(", " ")
.replace(":", " ").replace("", " ").split())
wordlist = open(path).read().replace("\n", " ").replace(")", " ").replace("(", " ").replace("", " ")
unique = [word for word, count in word_counts.items() if count == 1]
for word in unique:
text = wordlist
text.replace(word, str(word.upper()))
print(text)
它只打印常规文本,而没有进行任何修改。
事实上,我知道第一部分起作用,这只是最后的for循环,这给我带来了麻烦。
知道我在搞砸吗?
答案 0 :(得分:4)
替换此行
.slidecontainer {
width: 100%;
}
.slider {
-webkit-appearance: none;
width: 100px;
height: 15px;
border-radius: 5px;
background: #d3d3d3;
outline: none;
-webkit-transition: .2s;
transition: opacity .2s;
position: relative;
top: 130px;
opacity:0;
}
.slider:hover {
opacity: 1;
}
.slider::-webkit-slider-thumb {
-webkit-appearance: none;
appearance: none;
width: 25px;
height: 25px;
border-radius: 50%;
background: #4CAF50;
cursor: pointer;
}
.slider::-moz-range-thumb {
width: 25px;
height: 25px;
border-radius: 50%;
background: #4CAF50;
cursor: pointer;
}
使用
<meta name="viewport" content="width=device-width, initial-scale=1">
<div class="slidecontainer">
<input type="range" min="0" max="100" value="100" class="slider" id="volume">
</div>
<img id="Coffee" src="https://static.wixstatic.com/media/38d0c2_f65cba752ac3460da7a56896d1195284~mv2.png"
height="100" width="100">
<audio id="CoffeeAudio" loop>
<source src="//music.wixstatic.com/preview/38d0c2_02a2ea74abbc49a29ae7bdfabd1091d0-128.mp3" type="audio/wav" />
</audio>
text.replace(word, str(word.upper()))
不会修改原始字符串实例。
答案 1 :(得分:1)
您应该将其分配回文本。
findViewById(R.id.myTitle)