Question

我想根据$ArrayToOrder中的列SecondArrayField2对$SecondArray进行排序，其中两个数组之间的链接为Field_3（在$ ArrayToOrder中）和{{1 }}在$ SecondArray中。

SecondArrayField1

所需结果如下：

$ArrayToOrder=Array
(
    [0] => Array
        (
            [Field_1] => 13
            [Field_2] => 15
            [Field_3] => 3
        )

    [1] => Array
        (
            [Field_1] => 25
            [Field_2] => 17
            [Field_3] => 2
        )

    [2] => Array
        (
            [Field_1] => 121
            [Field_2] => 20
            [Field_3] => 11
        )
)

$SecondArray=Array
(
    [0] => Array
        (
            [SecondArrayField1] => 11
            [SecondArrayField2] => Bruce                
        )

    [1] => Array
        (
            [SecondArrayField1] => 3
            [SecondArrayField2] => Arthur
        )

    [2] => Array
        (
            [SecondArrayField1] => 2
            [SecondArrayField2] => Mary
        )
)

Answer 1

这是您可以使用的摘录，

// first fetching key as SecondArrayField2 and SecondArrayField1 as value
$Field_3 = array_column($SecondArray, "SecondArrayField1","SecondArrayField2");
// sort by key alphabetically
ksort($Field_3);
//
$sorted = array_values(array_map(function($v) use ($ArrayToOrder) {
    // first fetched Field_3 matching with current value of $Field_3 in the order
    // get the index of matching Field_3
    // save it to sorted array its sub array
    return $ArrayToOrder[array_search($v, array_column($ArrayToOrder,'Field_3'))];
}, $Field_3));
print_r($sorted);die;

Demo。

输出：

Array
(
    [0] => Array
        (
            [Field_1] => 13
            [Field_2] => 15
            [Field_3] => 3 //(Arthur)
        )

    [1] => Array
        (
            [Field_1] => 121
            [Field_2] => 20
            [Field_3] => 11 // (Bruce)
        )

    [2] => Array
        (
            [Field_1] => 25
            [Field_2] => 17
            [Field_3] => 2 // (Mary)
        )

)

根据第二个数组对多维数组排序

1 个答案: