Ansible从列表中删除项目

Question

基于变量，我需要两个版本的“ same”列表，并且我想避免重复以下代码：

- set_fact: 
     type1: false    (or true!)

- set_fact:
    mylist: 
    - "show command1"
    - "show command2.1"
    - "show command3"
    - "show command4"
  when: type1

- set_fact:
    mylist: 
    - "show command1"
    - "show command2.1"
    - "show command2.2"
    - "show command3"
    - "show command4"
  when: not type1        

有没有办法（金贾）避免重复？

Riccardo Russo

Answer 1

我当前的解决方案是：

mytemplate.j2

mycmd:
- "show command1"
- "show command2.1"
{% if not type1 %}
- "show command2.2"
{% endif %}
- "show command3"
- "show command4"

plb.yaml

- set_fact:
    myvar: "{{ lookup('template', './mytemplate.j2') | from_yaml }}" 

- debug:
    var: myvar["cmd"]

Answer 2

您可以在merge lists中输入ansible：

- set_fact:
    mylist:
    - "show command1"
    - "show command2.1"
    - "show command3"
    - "show command4"

- set_fact:
    mylist: '{{ mylist | union([ "show command2.2" ]) }}'
  when: not type1

如果订单很重要，您可以对列表进行排序。

mylist: '{{ mylist | union([ "show command2.2" ]) | sort }}'