Question

我有这个代码。它只能用于单词。我需要类似的字符串或文本文档。

import re
from collections import Counter
def words(text): return re.findall(r'\w+', text.lower())
WORDS = Counter(words(open('big.txt').read()))
def P(word, N=sum(WORDS.values())): 
    "Probability of `word`."
    return WORDS[word] / N

def correction(word): 
    "Most probable spelling correction for word."
    return max(candidates(word), key=P)

def candidates(word): 
    "Generate possible spelling corrections for word."
    return (known([word]) or known(edits1(word)) or known(edits2(word)) or [word])

def known(words): 
    "The subset of `words` that appear in the dictionary of WORDS."
    return set(w for w in words if w in WORDS)

def edits1(word):
    "All edits that are one edit away from `word`."
    letters    = 'abcdefghijklmnopqrstuvwxyz'
    splits     = [(word[:i], word[i:])    for i in range(len(word) + 1)]
    deletes    = [L + R[1:]               for L, R in splits if R]
    transposes = [L + R[1] + R[0] + R[2:] for L, R in splits if len(R)>1]
    replaces   = [L + c + R[1:]           for L, R in splits if R for c in letters]
    inserts    = [L + c + R               for L, R in splits for c in letters]
    return set(deletes + transposes + replaces + inserts)

def edits2(word): 
    "All edits that are two edits away from `word`."
    return (e2 for e1 in edits1(word) for e2 in edits1(e1))

Answer 1

使用此代码遍历文本的所有单词，您就完成了！

text = "This is an exmple"
result = ""
for word in text.split():
    result += correction(word) + " "
print(result)

您只需要做的就是用单词词典填充'big.txt'文本文件。

Answer 2

标记文本是一项经过充分研究的任务。仅用空格字符分割单词并不总是能按预期工作。您可以使用https://github.com/cbaziotis/ekphrasis和https://github.com/mammothb/symspellpy之类的库。

如何纠正文本文档中的拼写错误（仅适用于单个单词）

2 个答案: