Question

我需要将字符串转换为十六进制格式，并将“ 0x”前缀附加到十六进制值。例如：

输入：std::string s = "0x06A4";

输出：int num = 0x06A4

我尝试了以下代码：

{
    std::stringstream ss;
    std::string s = "0x06A4";
    int num = std::stoi(s, 0, 16);
    std::cout << "value in decimal     = " << num << '\n';
    std::cout << "value in hexadecimal = " << std::hex << num << '\n';
    ss << "0x" << std::hex << num << '\n'; //
    std::string res = ss.str();
    std::cout << "result  " << res << '\n';
}

Answer 1

@yogita，std :: hex只是您需要的配置之一。您可能缺少setfill和setw配置，如下所示：

#include <iostream>
#include <sstream>
#include <iomanip>

int main()
{
    std::stringstream ss;
    std::string s = "0x06A4";

    int num = std::stoi(s, nullptr, 16);
    std::cout << "value in decimal     = " << num << '\n';
    std::cout << "value in hexadecimal = " << std::hex << num << '\n';
    ss << "0x" << std::hex << std::setfill('0') << std::setw(4) <<num << '\n';

    std::string res = ss.str();
    std::cout << "result  " << res << '\n';
    return 0;
}

将字符串转换为十六进制格式，并将“ 0x”附加到十六进制值

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