Question

我有点卡在这里，我想查找给定时间间隔内的所有星期数，但我真的无法弄清楚

例如，代替 - > datepart(week,dateadd(day,-1,@oneSingleDate))（星期一是一周的第一天），

我需要

- > datepart(week,@startDate,@endDate)

鉴于间隔'2019-01-04'-'2019-01-28'，输出必须为：

WeekNo：1,2,3,4,5。

Answer 1

我使用了递归CTE来生成范围内的所有日期，然后我使用DATEPART从中选择了DISTINCT周数。然后，我将您的逗号分隔的字符串连接到一个名为@OUT

的变量中

DECLARE @startDate as date = '20190104';
DECLARE @endDate as date = '2019-01-28';

DECLARE @OUT as nvarchar(max);

WITH CTE AS (SELECT @startDate As X
             UNION ALL
             SELECT DATEADD(y, 1, X) X FROM CTE where x < @endDate),
    CTE2 AS (SELECT DISTINCT datepart(wk, X) wk from cte)
    select @out = coalesce(@out + ', ', '') + cast(wk as nvarchar(4))  from cte2
    OPTION (MAXRECURSION 0);

    select @out;

Answer 2

您可以执行以下操作：使用： -[CTE] [1]常用表格表达 -[Sql递归联合全部] [2] -[将多行串联成一行] [3]

declare @startDate as date ;
declare @endDate as date ;
set @startDate='2019-01-04'; 
set @endDate='2019-01-28' ;
DECLARE @weeks VARCHAR(8000) ;
with cte as (select @startDate as mydate,datepart(week,@startDate) w
union all select
dateadd(day,1,mydate),datepart(week,dateadd(day,1,mydate))  from cte
where mydate < @endDate) , cte2 as (select distinct(w) from cte)
select @weeks=COALESCE(@weeks + ', ', '') +cast(w as varchar(2)) from
cte2 OPTION (MAXRECURSION 360) select @weeks [Result]

如何在T-SQL中查找给定时间间隔内的星期数

2 个答案: