从Cash_numbers GROUP BY wn_sum ORDER BY wn_sum ASC中选择wn_sum，COUNT（*）作为计数；极限搜索

Question

我有以下SQL语句：

SELECT wn_sum, COUNT(*) as count FROM cash_numbers GROUP BY wn_sum ORDER BY wn_sum ASC;

几乎可以满足我的要求，但是我想从wn_sum中选择第100行，或者从wn_sum中选择最后100行。

我将如何重写此语句以仅从wn_sum获取前100行或从wn_sum获取最后100行以获取计数？

mysql> SELECT wn_sum, COUNT(*) as count FROM cash_numbers GROUP BY wn_sum ORDER BY wn_sum ASC;

+--------+-------+
| wn_sum | count |
+--------+-------+
|     54 |     2 |
|     56 |     1 |
|     61 |     1 |
|     65 |     1 |
|     66 |     1 |
|     68 |     1 |
|     70 |     1 |
|     71 |     1 |
|     72 |     1 |
|     73 |     2 |
|     76 |     4 |
....
|    234 |     1 |
|    237 |     1 |
|    241 |     1 |
|    244 |     1 |
|    251 |     2 |
|    267 |     1 |
+--------+-------+
156 rows in set (0.00 sec)

mysql> 

我确实尝试将限制设置为100，但是我的语法错误，因此在尝试使用这些限制时会出错。