根据下面的2个表格,仅显示产品未脱机时的活动时间。请记住,这是一小部分数据。活动表中将有多个产品,脱机表中会有多个时间戳。
目标是在产品上线时输出。所以根据下面的数据,我需要一个将返回的查询:第3,6,7行 - 这些是产品在线时的时间戳。
mysql> select * from activity;
+------------+---------------------+
| product_id | activity_date |
+------------+---------------------+
| 1 | 2011-04-13 12:00:00 |
| 1 | 2011-04-13 01:00:00 |
| 1 | 2011-04-13 02:00:00 |
| 1 | 2011-04-13 03:00:00 |
| 1 | 2011-04-13 04:00:00 |
| 1 | 2011-04-13 05:00:00 |
| 1 | 2011-04-13 06:00:00 |
+------------+---------------------+
7 rows in set (0.01 sec)
mysql> select * from offline
+------------+---------------------+---------------------+
| product_id | offline_start | offline_end |
+------------+---------------------+---------------------+
| 1 | 2011-04-13 12:00:00 | 2011-04-13 01:00:00 |
| 1 | 2011-04-13 03:00:00 | 2011-04-13 04:00:00 |
+------------+---------------------+---------------------+
2 rows in set (0.01 sec)
答案 0 :(得分:0)
create table activity
(
product_id int,
activity_date datetime
);
create table [offline]
(
product_id int,
offline_start datetime,
offline_end datetime
);
insert into activity(product_id, activity_date)
values (1, '2011-04-13 12:00:00 AM')
,(1, '2011-04-13 01:00:00 AM')
,(1, '2011-04-13 02:00:00 AM')
,(1, '2011-04-13 03:00:00 AM')
,(1, '2011-04-13 04:00:00 AM')
,(1, '2011-04-13 05:00:00 AM')
,(1, '2011-04-13 06:00:00 AM');
insert into [offline](product_id, offline_start, offline_end)
values (1, '2011-04-13 12:00:00 AM', '2011-04-13 01:00:00 AM')
,(1, '2011-04-13 03:00:00 AM', '2011-04-13 04:00:00 AM');
select a.*
from activity a
left join offline o
on a.product_id = o.product_id
and a.activity_date between o.offline_start and o.offline_end
where o.product_id IS NULL
在家中没有设置mysql服务器来测试它,但如果AM不起作用,那么上午12点是00:00:00所以活动表上的第一个条目应该是
1, '2011-04-13 00:00:00'
并且离线表的第一个条目应为
1, '2011-04-13 00:00:00', '2011-04-13 01:00:00'
在我的sql server上测试了这个,这是输出:
product_id activity_date
1 2011-04-13 02:00:00.000
1 2011-04-13 05:00:00.000
1 2011-04-13 06:00:00.000