Question

让我们使用以下代码示例详细说明我的问题：

struct exampleObj {
    var str: String?
    var arr: [String]?
}

let filterArray = ["something1", "ins1", "something2"]

let obj1 = exampleObj(str: "obj1", arr: ["ins2", "ins3"])
let obj2 = exampleObj(str: "obj2", arr: ["ins1", "ins2"])
let obj3 = exampleObj(str: "obj3", arr: ["ins1", "ins4"])
let obj4 = exampleObj(str: "obj4", arr: ["ins3", "ins4"])

var arrayObj = [obj1, obj2, obj3, obj4]

let result = arrayObj.filter { filterArray.contains($0.arr...)} //??? I get lost here, dunno if right approach.

我想做的是通过使用另一个数组arrayObj来过滤filterArray，结果是在result上仅包含{{1 }}。

我希望我很清楚。对此问题有任何疑问，我在这里。

Answer 1

尝试一下：

let result = arrayObj.filter { obj in
    filterArray.contains { filter in
        obj.arr?.contains(filter) ?? false
    }
}

或使用Set：

let result = arrayObj.filter { !Set(filterArray).isDisjoint(with: $0.arr ?? []) }

Answer 2

您需要找到两个数组的值之间有交点的匹配项。使用集合更容易做到这一点。您还需要处理arr是可选的。

let result = arrayObj.filter { !Set(filterArray).intersection($0.arr ?? []).isEmpty }

如果您将filterArray声明为Set开始，这将更加有效。

let filterSet: Set = ["something1", "ins1", "something2"]

let obj1 = exampleObj(str: "obj1", arr: ["ins2", "ins3"])
let obj2 = exampleObj(str: "obj2", arr: ["ins1", "ins2"])
let obj3 = exampleObj(str: "obj3", arr: ["ins1", "ins4"])
let obj4 = exampleObj(str: "obj4", arr: ["ins3", "ins4"])

var arrayObj = [obj1, obj2, obj3, obj4]

let result = arrayObj.filter { !filterSet.intersection($0.arr ?? []).isEmpty }

Answer 3

您只需在non-empty和intersection之间找到filterArray exampleObj's arr，即可完成操作，即

let filterSet = Set(filterArray)
let result = arrayObj.filter { (exampleObj) -> Bool in
    if let arr = exampleObj.arr {
        return !filterSet.intersection(arr).isEmpty
    }
    return false
}

输出：：result包含obj1和obj2。

Answer 4

尝试一下

let result = arrObj.filter{ $0.arr.contains{ where : $0 as? String ?? "" == "ins1"} }

使用内部数组和另一个数组过滤对象数组

4 个答案: