我正在尝试创建此查询,以获取表上不存在日期的范围和数据中所有具有日期的完整日期
例如,这是我的 tbl_example
原始数据:
id | userid(str) | comment(str) | mydate(date)
1 0001 sample1 2019-06-20T16:00:00.000Z
2 0002 sample2 2019-06-21T16:00:00.000Z
3 0003 sample3 2019-06-24T16:00:00.000Z
4 0004 sample4 2019-06-25T16:00:00.000Z
5 0005 sample5 2019-06-26T16:00:00.000Z
然后:
select * from tbl_example where mydate between '2019-06-20' AND
DATE('2019-06-20') + interval '5 day')
如何输出范围中所有可能为null的日期
预期输出:
id | userid(str) | comment(str) | mydate(date)
1 0001 sample1 2019-06-20T16:00:00.000Z
2 0002 sample2 2019-06-21T16:00:00.000Z
null null null 2019-06-22T16:00:00.000Z
null null null 2019-06-23T16:00:00.000Z
4 0003 sample3 2019-06-24T16:00:00.000Z
5 0004 sample4 2019-06-25T16:00:00.000Z
这是我的示例测试环境:http://www.sqlfiddle.com/#!17/f5285/2
答案 0 :(得分:1)
SELECT id, userid, "comment", d.mydate
FROM generate_series('2019-06-20'::date, '2019-06-25'::date, INTERVAL '1 day') d (mydate)
LEFT JOIN tbl_example ON d.mydate = tbl_example.mydate
结果
答案 1 :(得分:1)
好的,请看下面的我的SQL:
with all_dates as (
select generate_series(min(mydate),max(mydate),'1 day'::interval) as dates from tbl_example
)
,null_dates as (
select
a.dates
from
all_dates a
left join
tbl_example t on a.dates = t.mydate
where
t.mydate is null
)
select null as id, null as userid, null as comment, dates as mydate from null_dates
union
select * from tbl_example order by mydate;
id | userid | comment | mydate
----+--------+---------+---------------------
1 | 0001 | sample1 | 2019-06-20 16:00:00
2 | 0002 | sample1 | 2019-06-21 16:00:00
| | | 2019-06-22 16:00:00
| | | 2019-06-23 16:00:00
3 | 0003 | sample1 | 2019-06-24 16:00:00
4 | 0004 | sample1 | 2019-06-25 16:00:00
5 | 0005 | sample1 | 2019-06-26 16:00:00
(7 rows)
或者通过generate_series
子句,您可以只编写所需的日期参数,如下所示:
select generate_series('2019-06-20 16:00:00','2019-06-20 16:00:00'::timestamp + '5 days'::interval,'1 day'::interval) as dates