Jcrop裁剪图像保存到数据库

Question

我想将裁剪后的图像保存在数据库中，但找不到任何方法。如何保存图像并从数据库中获取图像？我尝试过的是：

if (isset($_POST['submit']))
{
  $conn = mysqli_connect('localhost','pma','123','test');
  if(!$conn){
    echo mysqli_error($conn);
  }
    $targ_w = $targ_h = 200;
    $jpeg_quality = 90;
  $src = $_POST['img'];

  $ext = $_POST['ext'];
  $name = "image.".$ext;
  $newname = strstr($src,$name);

  $img_r = imagecreatefromjpeg($src);

  $dst_r = ImageCreateTrueColor( $targ_w, $targ_h );
    imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],
    $targ_w,$targ_h,$_POST['w'],$_POST['h']);

  if($ext == "png")
  {
      $img_r = imagecreatefrompng($src);
      imagepng($img_r,'ima.png',$jpeg_quality);
      header('Content-Type: image/png');
      $im     = imagecreatefrompng($src);
      $dst_r = ImageCreateTrueColor( $targ_w, $targ_h );
        imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],
      $targ_w,$targ_h,$_POST['w'],$_POST['h']);
      imagepng($dst_r,'image.png');
      imagedestroy($im);
  }else{
   $im = imagejpeg($dst_r,'image.jpg',$jpeg_quality);
    header('Content-type: image/jpeg');
    $localimage = dirname(__FILE__)."/demo_files/image.".$ext;
  if($conn){
      $sql = "INSERT INTO `celeb` (`img` ) VALUES ('$localimage')";
      $qry = mysqli_query($conn,$sql);
  }
  $sel = "SELECT * FROM `celeb` WHERE `image_name` ='772.jpeg' ";
  $selqry = mysqli_query($conn,$sel);
  while($row = mysqli_fetch_array($selqry)){
      echo '<img src ="'.$row['img'].'" id= "nnnn">';
  }
    exit;
  }

}

但是没有运气。