需要查询以获取员工姓名,即每个员工使用的总燃料。 如果员工不使用燃料,则第二列应有一个 文字“不使用燃料”。
以下是两个表:
Table1: EmployeeID, FirstName
1 Vikas
2 nikita
3 Ashish
4 Nikhil
5 anish
Table2: ID, Fuel
1 10
2 9
3 8
4 6
5 12
6 11
7 10
8 9
9 8
10 10
11 9
12 12
13 7
14 15
其中列table2.ID
是table1.EmployeeID
的外键。
这是我编写的代码,很可能是错误的。
select ID, FirstName, sum(table2.Fuel) sum_fuel
from table2,table1
where EmployeeID=ID IN (
select ID, coalesce(ID, 'No-fuel used') as ID
from table1 t1
left join table2 t2 on t2.ID = t1.EmployeeID
)
group by fuel
order by ID DESC;
从两个表中可以看到,表1中具有1到5的雇员在表2中。因此,对于这些员工,我需要显示每个人使用的总燃料。并且表1中没有ID为6至14的员工,因此应为这些员工打印“不使用燃料”消息。
答案 0 :(得分:1)
您可以使用left join
。这样,当表的ID值不匹配时,您将获得sum(fuel)
值的空值,并将为'No fuel used'
分配字符串sum_fuel
使用nvl()
函数创建列:
with table1( EmployeeID, FirstName ) as
(
select 1,'Vikas' from dual union all
select 2,'nikita' from dual union all
select 3,'Ashish' from dual union all
select 4,'Nikhil' from dual union all
select 5,'anish' from dual union all
select 15,'pratteek' from dual
), table2( ID, Fuel ) as
(
select 1, 10 from dual union all
select 2, 9 from dual union all
select 3, 8 from dual union all
select 4, 6 from dual union all
select 5, 12 from dual union all
select 6, 11 from dual union all
select 7, 10 from dual union all
select 8, 9 from dual union all
select 9, 8 from dual union all
select 10, 10 from dual union all
select 11, 9 from dual union all
select 12, 12 from dual union all
select 13, 7 from dual union all
select 14, 15 from dual
)
select EmployeeID, FirstName, nvl(to_char(sum(t2.Fuel)),'No fuel used') as sum_fuel
from table1 t1
left join table2 t2
on t1.EmployeeID = t2.ID
group by EmployeeID, FirstName
order by EmployeeID desc;
EMPLOYEEID FIRSTNAME SUM_FUEL
---------- --------- ------------
15 pratteek No fuel used
5 anish 12
4 Nikhil 6
3 Ashish 8
2 nikita 9
1 Vikas 10
答案 1 :(得分:0)
这可能有效---
SELECT ID
, FirstName
, CASE
WHEN SUM(f.Fuel) > 0 THEN CAST(SUM(f.Fuel) AS NVARCHAR(25))
ELSE 'No fuel used'
END sum_fuel
FROM #emp e
LEFT JOIN #fuel f ON e.EmployeeID = f.id
GROUP BY ID,FirstName
ORDER BY ID DESC