Question

我的控制台向我显示了所有分数的总和，但是我希望它显示32和35而不是65。最终结果是我想将每个总和压入一个数组。

var peopleArray = [
    {
        name: "Hector Valdes",
        photo: "",
        scores: [
            "5", "1", 
            "4", "4", 
            "5", "1", 
            "2", "5", 
            "4", "1" 
        ]
    }, {
        name: "Tyler Williams",
        photo: "",
        scores: [
            "5", "1",
            "4", "4",
            "5", "2",
            "2", "5",
            "4", "1"
        ]
    }
]

let total = 0;

for (i = 0; i < peopleArray.length; i++){
        for(j=0; j < peopleArray[i].scores.length; j++){
            total += Number(peopleArray[i].scores[j]);
            console.log(total);
        };
    };

Answer 1

var peopleArray = [
    {
        name: "Hector Valdes",
        photo: "",
        scores: [
            "5", "1", 
            "4", "4", 
            "5", "1", 
            "2", "5", 
            "4", "1" 
        ]
    }, {
        name: "Tyler Williams",
        photo: "",
        scores: [
            "5", "1",
            "4", "4",
            "5", "2",
            "2", "5",
            "4", "1"
        ]
    }
]

let total = peopleArray.map(i => {
  return i.scores.reduce((a, b) => parseInt(a) + parseInt(b), 0)
})
console.log(total)

Answer 2

您可以使用map遍历每个peopleArray元素。使用reduce对分数求和。

通过在字符串前添加+，将字符串转换为数字的一个选项。

var peopleArray = [{"name":"Hector Valdes","photo":"","scores":["5","1","4","4","5","1","2","5","4","1"]},{"name":"Tyler Williams","photo":"","scores":["5","1","4","4","5","2","2","5","4","1"]}];
var total = peopleArray.map(o => o.scores.reduce((c, v) => +c + +v));

console.log(total);

Answer 3

尝试一下

static createCar(req, res) {
    const { errors, isValid } = validateNewCar(req.body);
    if (!isValid) {
      return res.status(400).json({ errors });
    }
    const vehicle = {
      id: vehicles.length + 1,
      userId: 3,
      state: req.body.state,
      status: 'available',
      price: req.body.price,
      manufacturer: req.body.manufacturer,
      model: req.body.model,
      bodyType: req.body.bodyType
    };

    vehicles.push(vehicle);
    return res.status(201).json({
      status: 201,
      message: 'Vehicle created successfully',
      data: vehicle,
    });
  }

Answer 4

尝试一下

您需要在第一个循环中移动+----+---------+--------------+----------------+-------+---------------------------+ | id | team_id | scoreable_id | scoreable_type | state | created_at | +----+---------+--------------+----------------+-------+---------------------------+ | 1 | 3979 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | | 2 | 3717 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | | 3 | 3626 | 8 | SpecialPlace | draft | 2015-11-30 10:09:06 +0000 | | 4 | 3202 | 8 | SpecialPlace | draft | 2015-11-30 10:09:06 +0000 | | 5 | 703 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | | 6 | 278 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | | 7 | 3166 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | | 8 | 3147 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | | 9 | 3146 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | | 10 | 3145 | 2 | SpecialEvent | draft | 2015-11-30 10:09:06 +0000 | +----+---------+--------------+----------------+-------+---------------------------+，然后只需在数组中添加一个新的总对象即可。

declare @stmt1 varchar(max)
set @stmt1='insert into dbo.abcd SELECT [company],[address], 
[address2],[zip],[zip4],[city],[state], 
[telephone_number],LOWER([email]),[name],[fname],[mname],[lname], 
[title_full] FROM DBO.filter WHERE  
[id] in (''7'',''8'',''11'',''15'')  and contains 
(code,'+''''+'"0111" OR "4142"......................OR 
"5999"'+''''+')'
exec (@stmt1) AT [server]

Answer 5

尝试一下，希望对您有所帮助。

let scoresArr = peopleArray.map(data => {   
return data.scores.reduce((a,b) => parseFloat(a) + parseFloat(b), 0) 
})

console.log(scoresArr)

我有一个对象数组，每个对象内都有一个称为分数的键，我需要找到每个分数的总和并将其推入数组

5 个答案: