Question

我有一个需要过滤的用户代理列表。但是我没有做到。

例如，下面有5个useragent。表的名称为temp，列名称为useragent。我想在postgresql中返回前3个。

"Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/603.3.8 (KHTML, like Gecko) Version/10.0 Mobile/14G60 Safari/602.1"

"Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/602.1.50 (KHTML, like Gecko) GSA/33.0.164895372 Mobile/14G60 Safari/602.1"

"Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/603.3.8 (KHTML, like Gecko) Version/10.0 Mobile/14G60 Safari/602.1"

"POF 6.21.912; (iPhone8,2; iOS 10.3.3; en_US; g=ON; p=ON; r=WiFi) 0ADC1470-4814-4100-83A6-D9D4843F2DFA;"

"POF 6.21.912; (iPhone9,2; iOS 10.3.3; en_US; g=ON; p=ON; r=WiFi) D7CBD4C8-3482-4226-93DB-B8894AFFD087;"

这是我正在尝试的代码：

select useragent from temp where useragent  like `'^Mozilla/\\d\\.\\d\\s\\(iPhone*'`

它什么也不返回。谁能帮我解决这行语法吗？

Answer 1

请勿使用like，like只能检查一个字符串（例如'％abc％'）是否包含在另一个字符串（例如'kkabchh'）中，并且不适用于正则表达式。您应该在~中使用PostgreSQL，如下所示：

postgres=# select 'Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/603.3.8 (KHTML, like Gecko) Version/10.0 Mobile/14G60 Safari/602.1' ~ 'Mozilla.*iPhone.*' as bool;
 bool 
------
 t
(1 row)

postgres=# select useragent from temp where useragent ~ 'Mozilla.*iPhone.*';
                                                                   useragent                                                                    
------------------------------------------------------------------------------------------------------------------------------------------------
 Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/603.3.8 (KHTML, like Gecko) Version/10.0 Mobile/14G60 Safari/602.1
 Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/602.1.50 (KHTML, like Gecko) GSA/33.0.164895372 Mobile/14G60 Safari/602.1
 Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/603.3.8 (KHTML, like Gecko) Version/10.0 Mobile/14G60 Safari/602.1
(3 rows)

如何在PostgreSQL中匹配那些useragent字符串？

1 个答案: