Question

我有两个查询，当选择一个特定的单词时，我使用表达式来计数。这两个查询均按预期方式工作，但我想使用联合查询将其合并。联合有效，但是当两个查询中的代表姓名都出现时，它会两次列出该姓名。

运行联合会时，我收到以下信息

Rep     OppCount    DevCount    BiddingCount
Darrell    0            0           0
Josh       40           7           156
Kyle       0            0           15
Leah       26           4           55
Mark       59           8           159
Vic        25           2           191
Darrell    0            94          0
Josh       0            51          0
Kyle       0            62          0
Leah       0            101         0
Mark       0            87          1
Vic        0            8           0

SELECT Opp_New.Rep AS Rep, "" AS FaceToFaceCount, "" AS PhoneCount, "" AS EmailCount, Sum(IIf([Opp_New]![Status]="Opportunity",1,0)) AS OppCount, Sum(IIf([Opp_New]![Status]="Developing",1,0)) AS DevCount, Sum(IIf([Opp_New]![Status]="Bidding",1,0)) AS BiddingCount, Sum(IIf([Opp_New]![Status]="At MFG for Quote",1,0)) AS AtMFGCount, Sum(IIf([Opp_New]![Status]="Did Not Bid",1,0)) AS DNBCount, Sum(IIf([Opp_New]![Status]="Bid/Quote",1,0)) AS QuotedCount, Sum(IIf([Opp_New]![Status]="Won",1,0)) AS WonCount, Sum(IIf([Opp_New]![Status]="Lost",1,0)) AS LostCount
FROM Opp_New
GROUP BY Rep

UNION ALL

SELECT Calls_New.Rep AS Rep, Sum(IIf([Calls_New]![ContactType]="Face To Face",1,0)) AS FaceToFaceCount, Sum(IIf([Calls_New]![ContactType]="Phone",1,0)) AS PhoneCount, Sum(IIf([Calls_New]![ContactType]="Email",1,0)) AS EmailCount, Sum(IIf([Calls_New]![ProjectStatus]="Opportunity",1,0)) AS OppCount, Sum(IIf([Calls_New]![ProjectStatus]="Developing",1,0)) AS DevCount, Sum(IIf([Calls_New]![ProjectStatus]="Bidding",1,0)) AS BiddingCount, Sum(IIf([Calls_New]![ProjectStatus]="At MFG for Quote",1,0)) AS AtMFGCount, Sum(IIf([Calls_New]![ProjectStatus]="Did Not Bid",1,0)) AS DNBCount, Sum(IIf([Calls_New]![ProjectStatus]="Bid/Quote",1,0)) AS QuotedCount, Sum(IIf([Calls_New]![ProjectStatus]="Won",1,0)) AS WonCount, Sum(IIf([Calls_New]![ProjectStatus]="Lost",1,0)) AS LostCount
FROM Calls_New
GROUP BY Rep

我想像下面这样

Rep     OppCount    DevCount    BiddingCount
Darrell     0           94          0
Josh        40          58          156
Kyle        0           62          15
Leah        26          105         55
Mark        59          95          160
Vic         25          10          191

Answer 1

在我看来，您根本不需要使用UNION，而是要在INNER JOIN上使用rep。

SELECT t1.Rep, t1.OppCount + t2.OppCount As OppCount, t1.BiddingCount + t2.BiddingCount As BiddingCount
FROM (
    SELECT Opp_New.Rep AS Rep, "" AS FaceToFaceCount, "" AS PhoneCount, "" AS EmailCount, Sum(IIf([Opp_New]![Status]="Opportunity",1,0)) AS OppCount, Sum(IIf([Opp_New]![Status]="Developing",1,0)) AS DevCount, Sum(IIf([Opp_New]![Status]="Bidding",1,0)) AS BiddingCount, Sum(IIf([Opp_New]![Status]="At MFG for Quote",1,0)) AS AtMFGCount, Sum(IIf([Opp_New]![Status]="Did Not Bid",1,0)) AS DNBCount, Sum(IIf([Opp_New]![Status]="Bid/Quote",1,0)) AS QuotedCount, Sum(IIf([Opp_New]![Status]="Won",1,0)) AS WonCount, Sum(IIf([Opp_New]![Status]="Lost",1,0)) AS LostCount
    FROM Opp_New
    GROUP BY Rep
) t1
INNER JOIN (
    SELECT Calls_New.Rep AS Rep, Sum(IIf([Calls_New]![ContactType]="Face To Face",1,0)) AS FaceToFaceCount, Sum(IIf([Calls_New]![ContactType]="Phone",1,0)) AS PhoneCount, Sum(IIf([Calls_New]![ContactType]="Email",1,0)) AS EmailCount, Sum(IIf([Calls_New]![ProjectStatus]="Opportunity",1,0)) AS OppCount, Sum(IIf([Calls_New]![ProjectStatus]="Developing",1,0)) AS DevCount, Sum(IIf([Calls_New]![ProjectStatus]="Bidding",1,0)) AS BiddingCount, Sum(IIf([Calls_New]![ProjectStatus]="At MFG for Quote",1,0)) AS AtMFGCount, Sum(IIf([Calls_New]![ProjectStatus]="Did Not Bid",1,0)) AS DNBCount, Sum(IIf([Calls_New]![ProjectStatus]="Bid/Quote",1,0)) AS QuotedCount, Sum(IIf([Calls_New]![ProjectStatus]="Won",1,0)) AS WonCount, Sum(IIf([Calls_New]![ProjectStatus]="Lost",1,0)) AS LostCount
    FROM Calls_New
    GROUP BY Rep
) t2 ON t1.Rep = t2.Rep

当然，在使用INNER JOIN时，您可以报废stuf，例如第一个查询中的空FaceToFaceCount，PhoneCount和EmailCount，而不必添加它们。由于您从示例输出中排除了它们，因此我没有将它们包括在外部查询中，但是应该很容易进行调整。

Answer 2

只需通过sum()函数汇总结果列

SELECT Rep,  
       sum(OppCount) as OppCount,  
       sum(DevCount) as DevCount, 
       sum(BiddingCount) as BiddingCount
 FROM 
(
   SELECT Opp_New.Rep AS Rep, "" AS FaceToFaceCount, "" AS PhoneCount, "" AS EmailCount, Sum(IIf([Opp_New]![Status]="Opportunity",1,0)) AS OppCount, Sum(IIf([Opp_New]![Status]="Developing",1,0)) AS DevCount, Sum(IIf([Opp_New]![Status]="Bidding",1,0)) AS BiddingCount, Sum(IIf([Opp_New]![Status]="At MFG for Quote",1,0)) AS AtMFGCount, Sum(IIf([Opp_New]![Status]="Did Not Bid",1,0)) AS DNBCount, Sum(IIf([Opp_New]![Status]="Bid/Quote",1,0)) AS QuotedCount, Sum(IIf([Opp_New]![Status]="Won",1,0)) AS WonCount, Sum(IIf([Opp_New]![Status]="Lost",1,0)) AS LostCount
     FROM Opp_New
    GROUP BY Rep    
    UNION ALL    
   SELECT Calls_New.Rep AS Rep, Sum(IIf([Calls_New]![ContactType]="Face To Face",1,0)) AS FaceToFaceCount, Sum(IIf([Calls_New]![ContactType]="Phone",1,0)) AS PhoneCount, Sum(IIf([Calls_New]![ContactType]="Email",1,0)) AS EmailCount, Sum(IIf([Calls_New]![ProjectStatus]="Opportunity",1,0)) AS OppCount, Sum(IIf([Calls_New]![ProjectStatus]="Developing",1,0)) AS DevCount, Sum(IIf([Calls_New]![ProjectStatus]="Bidding",1,0)) AS BiddingCount, Sum(IIf([Calls_New]![ProjectStatus]="At MFG for Quote",1,0)) AS AtMFGCount, Sum(IIf([Calls_New]![ProjectStatus]="Did Not Bid",1,0)) AS DNBCount, Sum(IIf([Calls_New]![ProjectStatus]="Bid/Quote",1,0)) AS QuotedCount, Sum(IIf([Calls_New]![ProjectStatus]="Won",1,0)) AS WonCount, Sum(IIf([Calls_New]![ProjectStatus]="Lost",1,0)) AS LostCount
     FROM Calls_New
    GROUP BY Rep
) q
GROUP BY Rep

如何在Access中修复联合命令

2 个答案: