Question

1-我准备好将代码转换为xml到csv的代码。但是实际上我需要多次执行此操作，然后每次都需要在程序中更改xml文件的名称。我想做一个循环以读取文件夹位置中的每个'.xml'文件并为所有文件。有我的原始密码

import xml.etree.ElementTree as ET
import csv

tree = ET.parse("Shot_30AA.xml")
root = tree.getroot()

Shot_30AA = open('Shot_30AA.csv', 'w', newline='')
csvwriter = csv.writer(Shot_30AA)
head = []

ShotCode = root.attrib['ShotCode']
csvwriter.writerow(['ShotCode', ShotCode])
head.append(ShotCode)

for member in root.getchildren():
  submembers = member.getchildren()
  keys = submembers[0].attrib.keys()
  csvwriter.writerow ("\n")
  csvwriter.writerow(keys)
  for submember in submembers:
    row_data = [submember.attrib[k] for k in keys]
    csvwriter.writerow(row_data )
Shot_30AA.close()

我试图在我的文件夹中执行此操作，添加了休闲代码，只能执行一次

path = 'C:/Users/Desktop/Program'
for filename in os.listdir(path):
   if not filename.endswith('.xml'): continue
     ShotFile = os.path.join(path, filename)
     tree = ET.parse(ShotFile)
     root = tree.getroot()

     filename = open( filename'.csv', 'w', newline='')
     csvwriter = csv.writer(filename)
     head = [] 

     ShotFile = open('ShotFile.csv', 'w', newline='')
     csvwriter = csv.writer(Shot_30AA)
     head = []

     ShotCode = root.attrib['ShotCode']
     csvwriter.writerow(['ShotCode', ShotCode])
     head.append(ShotCode)

     for member in root.getchildren():
       submembers = member.getchildren()
       keys = submembers[0].attrib.keys()
       csvwriter.writerow ("\n")
       csvwriter.writerow(keys)
       for submember in submembers:
         row_data = [submember.attrib[k] for k in keys]
         csvwriter.writerow(row_data )
  ShotFile.close()

我希望一次运行即可获得csv格式的所有文件。

Answer 1

根据您的代码，这可能会起作用

def make_csv(folderpath, xmlfilename):
    tree = ET.parse(os.path.join(folderpath, xmlfilename))
    root = tree.getroot()
    filename, _ = xmlfilename.rsplit('.', 1)
    Shot_30AA = open(filename+'.csv', 'w', newline='')
    csvwriter = csv.writer(Shot_30AA)
    head = []

    ShotCode = root.attrib['ShotCode']
    csvwriter.writerow(['ShotCode', ShotCode])
    head.append(ShotCode)

    for member in root.getchildren():
        submembers = member.getchildren()
        keys = submembers[0].attrib.keys()
        csvwriter.writerow("\n")
        csvwriter.writerow(keys)
        for submember in submembers:
            row_data = [submember.attrib[k] for k in keys]
            csvwriter.writerow(row_data)
    Shot_30AA.close()

path = 'C:/Users/Desktop/Program'
for filename in os.listdir(path):
    if filename.endswith('.xml'):
        make_csv(path, filename)

编辑1：正如评论所指出的，在处理文件时，您还应该看看with open() as clause

如何使用python转换csv文件中的文件夹中的多个xml文件？

1 个答案: