Question

如何配置TypeScript以隐藏窗口中的所有全局变量，仅访问窗口本身？

示例：

此代码可以正常工作：

function foo(length: number): void {
  // Console result: A number from this scope.
  console.log(length);
}

但是当我删除参数length时。短毛绒仍然满意。因为length是window的全局变量。 See docs

function foo(): void {
  // Console result: A number from window. (not expected in this case)
  console.log(length);
}

预期：

function foo(): void {
  // Console result: undefined (or my global variable if exist)
  // And in case the variable does not exist, the linter will cry as expected.
  console.log(length);
}

我想在全局访问中隐藏窗口范围。但是我仍然希望访问窗口对象本身，如果我将其称为：

function foo(): void {
  // This already works. But length itself without window as context should fail.
  console.log(window.length);
}

是否有tsconfig或tslint选项？

Answer 1

检查https://palantir.github.io/tslint/rules/no-restricted-globals/ tslint版本> = 5.13.0

如何配置TypeScript以从窗口隐藏所有全局变量，但访问窗口本身？

1 个答案: