我想知道如何在Windows上下文菜单中将文件名传递给make命令。
我设法做到了
function Get-MsiProductCode {
[CmdletBinding()]
param (
[Parameter(Mandatory=$true)]
[ValidateScript({$_ | Test-Path -PathType Leaf})]
[string]$Path
)
function Get-Property ( $Object, $PropertyName, [object[]]$ArgumentList ) {
return $Object.GetType().InvokeMember($PropertyName, 'Public, Instance, GetProperty', $null, $Object, $ArgumentList)
}
function Invoke-Method ( $Object, $MethodName, $ArgumentList ) {
return $Object.GetType().InvokeMember( $MethodName, 'Public, Instance, InvokeMethod', $null, $Object, $ArgumentList )
}
$ErrorActionPreference = 'Stop'
Set-StrictMode -Version Latest
#http://msdn.microsoft.com/en-us/library/aa369432(v=vs.85).aspx
$msiOpenDatabaseModeReadOnly = 0
$Installer = New-Object -ComObject WindowsInstaller.Installer
$Database = Invoke-Method $Installer OpenDatabase $Path, $msiOpenDatabaseModeReadOnly
$View = Invoke-Method $Database OpenView "SELECT Value FROM Property WHERE Property='ProductCode'"
[void]( Invoke-Method $View Execute )
$Record = Invoke-Method $View Fetch
if ( $Record ) {
Get-Property $Record StringData 1
}
[void]( Invoke-Method $View Close @() )
Remove-Variable -Name Record, View, Database, Installer
}
效果很好。但是做这样的事情根本行不通
[HKEY_CLASSES_ROOT\Directory\Background\shell\cygwin_bash_mi\command]
@="D:\\cygwin\\bin\\bash.exe -c 'make install'"
我什至试图将%1更改为%〜nx1和%〜nxI,但是它也不起作用。 有解决办法吗?