Question

我为php实践创建了一个小应用程序。我已经成功创建了登录和插入功能。我在dashboard.php上遇到删除功能错误。

登录page。

用户名：admin 密码：12345

以下是dashboard.php文件的php代码：

<?php
include 'conntect.php';
    if (isset($_GET['delete'])){
        $del=$_GET['delete'];
        $sql="delete from partners where partner_id=".$del;
        mysqli_query($conn, $sql);
        header('location:dashboard.php');
    }



mysqli_close($conn);
?>
<td><a href="dashboard.php?delete='.$row["partner_id"].'" style="color:red;"><i class="far fa-window-close"></i></a></td>

当我单击删除图标时，我想从数据库中删除记录。

Answer 1

将您的<td>替换为以下代码：

<td><a href="dashboard.php?delete=<?php echo $row["partner_id"]; ?>" style="color:red;"><i class="far fa-window-close"></i></a></td>

如果进一步使用mysqli，请不要关闭MySQL连接。

Answer 2

您需要共享“ connect.php”文件的内容。出现错误的原因是因为“ mysqli_query（$ conn，$ sql）”期望参数1是（mysqli $ link）或（mysqli $ object）。

选中此 =>（ https://php.net/manual/en/mysqli.query.php ）

面向对象的样式 mysqli :: query（字符串$ query [，int $ resultmode = MYSQLI_STORE_RESULT]）：混合

程序样式 mysqli_query（mysqli $ link，字符串$ query [，int $ resultmode = MYSQLI_STORE_RESULT]）：混合

要进行快速修复，可以将我的这段代码放入connect.php文件中

    class Connect {
      private $DB_NAME = 'db_name'; //database name
      private $DB_HOST = 'localhost'; //database host
      private $DB_USER = 'root';  //database user
      private $DB_PASS = ''; //database password
      private $QUERY_DEBUG = 'on'; //enable debug locally and disable in production

      public static $conn;
      public static $pdo_conn;

       /**
        constructor function
       **/
       public function __construct() {
            try{
                //initialize a static mysqli connection object or die on error
                self::$conn = new mysqli($this->DB_HOST, $this->DB_USER, $this->DB_PASS, 
                $this->DB_NAME)or 
               die('unable to select Database, Connection Error'.  mysqli_error());
              } catch (Exception $e) {
                 die('unable to select Database, Connection Error'. $e->getMessage());
              }
           /**
             //if you are using pdo, uncomment this block of code
             $pdo = "mysql:host=" . $this->DB_HOST . ";dbname=" . $this->DB_NAME;
             try{
                 self::$pdo_conn = new PDO($pdo, $this->DB_USER, $this->DB_PASS);
             }catch (Exception $e)
             {
                die('unable to select Database, Connection Error'. $e->getMessage());
             }
         **/
       }

      /**
        function to encapsulate your queries
      **/
      public function safeQuery($query="") 
     {
        if(empty($query)){return false;}
        if($this->QUERY_DEBUG == "off")//check query debug mode
        {
            //$result = mysqli_query(self::$conn,$query) -> procedural way
            $result = self::$conn->query($query) or 
            die("An error occured");
        }
        else
        {
            //$result = mysqli_query(self::$conn,$query) -> procedural way
            $result = self::$conn->query($query)
            or die("query falied:"."<li>ERROR_NO = ".mysqli_errno(self::$conn)." 
          <li>ERROR= ".  mysqli_error(self::$conn).$query); 
        }
        return $result;
     }
   }

然后，要在代码中的任何位置使用mysqli查询，只需执行此操作

<?php
   include 'conntect.php';
    $conn = new Connect(); 
    //**Note** $conn exposes a static $conn property(which is a mysqli connection object
    if (isset($_GET['delete'])){
        $del=$_GET['delete'];
        $sql="delete from partners where partner_id=".$del;
        $conn->safeQuery($sql); // (Recommended) Object oriented way
        //mysqli_query($conn::$conn, $sql); // procedural way
        header('location:dashboard.php');
    }



//mysqli_close($conn::$conn);
?>
<td><a href="dashboard.php?delete='.$row["partner_id"].'" style="color:red;"><i class="far fa-window-close"></i></a></td>

我希望我能够提供帮助吗？如果是，请接受我的回答。最好的问候

Answer 3

$ sql =“从合作伙伴处删除，其中partner_id ='{$ del}'”;

我在核心php应用程序中遇到删除操作错误

3 个答案: